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3 years ago

Which equations show the identity property of multiplication?

Mathematics

1 answer:

Lady bird [3.3K]3 years ago

3 0

My answer is a and c becuase they equal the same on each side

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Which function is a horizontal translation of the parent quadratic function, f(x)=x^2?<br> HELP PLS

Elenna [48]

Answer:

f(x)=

${x}^{2} + 8$

${x}^{2} - 4$

5 0

3 years ago

Find 0.<br>Trigonometry problems.

aivan3 [116]

In the triangle with legs 7 and 9 cm, you can find the length of the hypotenuse by using the Pythagorean theorem. If the hypotenuse is $x$ , then

$7^2+9^2=x^2\implies x=\sqrt{130}$

The other right triangle with leg 6 cm and containing the angle $\theta$ satisfies

$\sin\theta=\dfrac{6\,\rm cm}{\sqrt{130}\,\rm cm}\implies\theta=\sin^{-1}\dfrac6{\sqrt{130}}\approx31.75^\circ$

6 0

2 years ago

What is the value of X?

Ugo [173]

∆ABC similar to ∆CBD

DB/AC = CB/AB

$\frac{x}{7.5} = \frac{7.5}{x + 3} \\ x(x + 3) = {7.5}^{2} = { (\frac{15}{2}) }^{2} \\ {x}^{2} + 3x = \frac{225}{4} \\ 4 {x}^{2} + 12x = 225 \\ 4 {x}^{2} + 12x + 9 = 216 \\ {(2x + 3)}^{2} = 216 \\ 2x + 3 = 6 \sqrt{6} \\ x = - 1.5 + 3 \sqrt{6}$

approximately 6.1485

4 0

3 years ago

Which statement correctly compares the two functions shown?

krok68 [10]

Answer:

Step-by-step explanation:

For Function 2

x=1 y=8

x=2 y=11

8=m+b

11=2m+b

11-8=2m-m

m=3

8=3+b

b=5

y=3x+5

Function 1

y=4x+5

Function 2

y=3x+5

....................

Function 1 has the same y-intercept and greater slope than Function 2.

4 0

2 years ago

Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat

yulyashka [42]

Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

$P(t) = 0.8t^{2} + 6t + 19000$

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

$P(t) = 0.8t^{2} + 6t + 19000$

$0.8t^{2} + 6t + 19000 = 34200$

$0.8t^{2} + 6t - 15200 = 0$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$0.8t^{2} + 6t - 15200 = 0$

So $a = 0.8, b = 6, c = -15200$

Then

$\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356$

$t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14$

$t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64$

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

6 0

2 years ago