How do you factor x^4-36?

Mathematics

2 answers:

Anettt [7]3 years ago

6 0

X4 over nothing-36 hope this willl work

juin [17]3 years ago

5 0

The solution to your problem is as follows:

<span>x^4 - 36=(x^2+6)(x^2-6)
</span>
Therefore, the factors of x^4-36 are <span>(x^2+6) and (x^2-6).

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>

You might be interested in

Find the discriminant of X^2+ 4x - 3 = 0

Drupady [299]

Answer:

2 real solutions

Step-by-step explanation:

Given a quadratic equation in standard form

ax² + bx + c = 0 ( a ≠ 0 ), then the discriminant is

Δ = b² - 4ac

• If b² - 4ac > 0 then 2 real and distinct solutions

• If b² - 4ac = 0 then 2 real and equal solutions

• If b² - 4ac < 0 then no real solutions

x² + 4x - 3 = 0 ← is in standard form

with a = 1, b = 4, c = - 3 , then

b² - 4ac = 4² - (4× 1 × - 3) = 16 - (- 12) = 16 + 12 = 28

Since b² - 4ac > 0 then the equation has 2 real and distinct solutions

5 0

3 years ago

"your friend is more than 3 minutes late" write four numbers that make the statement true plz answer

topjm [15]

Any number bigger than 3
4,5,6,7 are 4 numbers

6 0

3 years ago

PLEASE HELP ITS MY TRIMESTER TEST MY MOM WILL KILL ME IF I FAIL! <3 WILL MARK BRAINLIST!

Masteriza [31]

Answer:

$area = area \: of \: two \: semi \: circles + area \: of \: rectangle \\ = 2( \frac{1}{2} \pi {r}^{2} ) + (l \times w) \\ = 2( \frac{1}{2} \times 3.14 \times { (\frac{18}{2}) }^{2} ) + (18 \times 4.5) \\ = 254.47 + 81 \\ = 335.5 \: {ft}^{2}$