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yanalaym [24]
4 years ago
10

Function g is defined below.

Mathematics
2 answers:
const2013 [10]4 years ago
8 0
<span>
For the first question:<span>
Always remember some general rules of transformation, which are
</span> y= f(x+h)+ k<span>
-Shifts the graph of f left h units if h> 0
-Shifts the graph of f right |h| units if h< 0
-Shifts the graph of f up k units if K> 0
-Shifts the graph of f down |k| units if k< 0

In our question ,
</span>g(x) = f(x +2) – 5<span>--------1
Graph of f is shifted left by </span><span>two units due +2 in the given formula 1 and due to -5 graph of f is shifted down by 5 units.

For the second question: </span><span>
By general notation of function,
y=f(x)
when x=4 then
-3=f(4)
In the formula 1, x must be 2 to get f(4) and after that by putting -3 in place of f(4) we get  
g(2)=f(2+2)-5
g(2)=-3-5
</span> g(2)=-8<span>
If the point (4,-3) is on the graph of function f, then the point (2,-8) will be on the graph of function g.
</span></span>
Elina [12.6K]4 years ago
6 0
Rule: if you have graph of function y=f(x) and a>0, then:
1. y=f(x-a) is translation a units right;
2. y=f(x+a) is translation a units left;
3. y=f(x)-a is translation a units down;
4. y=f(x)+a is translation a units up;

Since g(x)=f(x+2)-5, then firstly you have to translate the graph of function y=f(x) two units left and secondly 5 units down.


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butalik [34]

Answer:

The volume of the metal used is 5277.9 cm³.

Step-by-step explanation:

The volume of a cylinder is given by:

V = \pi r^{2} h

Where:

r: is the radius

h: is the height = 50 cm

The volume of metal (V_{m}) can be found by subtracting the internal volume (V_{i}) from the external volume (V_{e}):

V_{m} = V_{e} - V_{i}

V_{m} = \pi r_{e}^{2} h - \pi r_{i}^{2} h    

The external radius is given by the sum of the internal radius with the tickness:

r_{e} = t + r_{i}

Hence, the volume is:

V_{m} = \pi*50 cm((2.4 cm + 5.8 cm)^{2} - (5.8 cm)^{2}) = 5277.9 cm^{3}

           

Therefore, the volume of the metal used is 5277.9 cm³.

I hope it helps you!                                                      

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