Answer:
Condition A.
A rectangle with four right angles
There can be many quadrilaterals satisfying this condition.
Condition B.
A square with one side measuring 5 inches
There can be only one quadrilateral satisfying this condition.
Condition C.
A rhombus with one angle measuring 43°
There can be many quadrilaterals satisfying this condition.
Condition D.
A parallelogram with one angle measuring 32°
There can be many quadrilaterals satisfying this condition.
Condition E.
A parallelogram with one angle measuring 48° and adjacent sides measuring 6 inches and 8 inches.
There can be only one quadrilateral satisfying this condition.
Condition F.
A rectangle with adjacent sides measuring 4 inches and 3 inches.
There can be only one quadrilateral satisfying this condition
Step-by-step explanation:
-mnp(3m - 5n + 7p) =
-3m^2np + 5mn^2p - 7mnp^2 <==
Solution
Step 1
The opposite angles of a parallelogram are equal:
Step 2

The equation is made true by the opposite angles theorem is
85 + y = 3y - 15
or
y = 50