Answer:
<h2>x³ + 8x² - 3x - 24 = (x + 8)(x - √3)(x + √3)</h2>
Step-by-step explanation:
![x^3+8x^2-3x-24\\\\=(x^2)(x)+(x^2)(8)+(-3)(x)+(-3)(8)\qquad\text{distribute}\\\\=x^2(x+8)-3(x+8)\\\\=(x+8)(x^2-3)\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=(x+8)(x^2-(\sqrt3)^2)\\\\=(x+8)(x-\sqrt3)(x+\sqrt3)](https://tex.z-dn.net/?f=x%5E3%2B8x%5E2-3x-24%5C%5C%5C%5C%3D%28x%5E2%29%28x%29%2B%28x%5E2%29%288%29%2B%28-3%29%28x%29%2B%28-3%29%288%29%5Cqquad%5Ctext%7Bdistribute%7D%5C%5C%5C%5C%3Dx%5E2%28x%2B8%29-3%28x%2B8%29%5C%5C%5C%5C%3D%28x%2B8%29%28x%5E2-3%29%5Cqquad%5Ctext%7Buse%7D%5C%20a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5C%5C%5C%5C%3D%28x%2B8%29%28x%5E2-%28%5Csqrt3%29%5E2%29%5C%5C%5C%5C%3D%28x%2B8%29%28x-%5Csqrt3%29%28x%2B%5Csqrt3%29)
Answer: 6.92 m
Step-by-step explanation:
Assuming the image is the attached below, we have a right triangle, where one of the legs is the 4 m high pole and the other leg the shadow.
Now, the tangent function is defined as:
![tan \theta=\frac{Opposite-leg}{Adjacent-leg}](https://tex.z-dn.net/?f=tan%20%5Ctheta%3D%5Cfrac%7BOpposite-leg%7D%7BAdjacent-leg%7D)
Since the Sun is at an angle
and the adjacent leg is the shadow
we have:
![tan(30\°)=\frac{4 m}{s}](https://tex.z-dn.net/?f=tan%2830%5C%C2%B0%29%3D%5Cfrac%7B4%20m%7D%7Bs%7D)
Isolating
:
![s=\frac{4 m}{tan(30\°)}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B4%20m%7D%7Btan%2830%5C%C2%B0%29%7D)
This is the length of the shadow
Answer:
22 in
Step-by-step explanation:
The formula for area is ...
A = 1/2bh
Filling in the given values, we have ...
22 = 1/2(2)h
22 = h . . . . simplify
The height is 22 inches.
Answer:
c. infinite solutions
Step-by-step explanation:
y = 10x + 2
This is a line. A line has infinite points
Therefore this has infinite solutions
Answer:in a the triangle is isosceles therefore it bisects triangle equally into two 90°
B they add up to 180°
C Within the individual triangles they add up to 180°
Step-by-step explanation:I hope this helps