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Kipish [7]
3 years ago
11

Which of the following terms is defined by "a line, segment, or ray that intersects the midpoint of a line segment at a 90 degre

e angle”?
A. Angle bisector
B. Midpoint
C. Segment Bisector
Or, D.. perpendicular bisector ?!
Mathematics
2 answers:
Artyom0805 [142]3 years ago
7 0

Answer:

C. Segment Bisector

Step-by-step explanation:

fomenos3 years ago
7 0
A because wow I know because i see pople use it everyday
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Hell me please 1 isnt right
Ber [7]

Step-by-step explanation:

I got this much.....

I am sorry of it gets wrong

6 0
2 years ago
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If x=73, what does 4x+3 equal?
never [62]
4(73)+3
273+3
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 Because you have to subsititue 73 for x. So you have to multiply 73 by 4 then what you get out of that you have to add it by 3.

5 0
3 years ago
Which is the correct use of the distributive property?
sergiy2304 [10]

Answer:

42+18=6(7+3)

Step-by-step explanation:

6x7=42 and 6x3=18

4 0
3 years ago
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How do you find the quotient of -4.8 divided by 0.6
Dafna11 [192]

Answer:

Step-by-step explanation:

− 4.8 /0.6 =−8

3 0
3 years ago
Needs to be in fraction form and simplified <br><br> 3 4/5 + 4 5/6 =? <br><br> 10 points
LenaWriter [7]

Answer:

259/30 or 8 19/30 depending on what format your teacher wants the answer

Step-by-step explanation:

First we can turn both mixed fractions into improper fractions and to do that we multiply the whole number by the denominator and that add that to the top number.  So for 3 4/5 we would multiply 3 and 5 and than add 4 getting us to 19/5 doing the same to 4 5/6 gets us to 29/6.  Now in order to add fractions we need to get a common denominator.  The least common multiple of 5 and 6 is 30 so we will multiply each fraction by whatever number will give us 30 in the denomiator.  for 19/5 that number is 6 so our new fraction is 114/30 and for 29/6 that number is 5 so our new number is 145/30.  Now we just add the numerators and simplify.  114/30+145/30=259/30

I hope this helps and please don't hesitate to ask if there is anything still unclear!

6 0
3 years ago
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