A proportional relationship is a relationship which crosses through the origin (0,0) and which has a proportional constant. We can determine this either by finding (0,0) where x=0 and y=0 in the table or by dividing y/x. None of the tables contain (0,0) so we will divide y by x. We are looking for a table which when each y is divided by its x we have the same constant appearing.

Table A

$\frac{12}{3} \neq \frac{15}{6} \neq \frac{18}{8} \neq \frac{20}{10}$

These fractions are not equal. This is not proportional.

Table B

$\frac{0.5}{1}=\frac{1}{2} =\frac{3.5}{7} =\frac{4}{8}$

These fractions are equal and each shows the numerator to be half of the denominator. This is proportional.

Table C

$\frac{1}{3}\neq \frac{2.5}{7.5} \neq \frac{4}{15} \neq \frac{6}{20}$

These fractions are not equal. This is not proportional.

Table D

$\frac{7}{2} \neq \frac{9}{3}\neq \frac{11}{4} \neq \frac{13}{5}$

These fractions are not equal. This is not proportional.

3 0

3 years ago

A city's population is increasing at a rate of 2% per year.

Mariana [72]

Based on the information the number of people that will there after 20 years is: d.) 2.97 million.

Using this formula

P(t) = Population ×(1+ rate)^t

Where:

Population=2 million

rate=2%

time=20 years

Let plug in the formula

P(t) = 2×(1+.02)^20

P(t) = 2×(1.02)^20

P(t) = 2×1.485947

P(t) = 2.97 million

Inconclusion the number of people that will there after 20 years is: d.) 2.97 million.

Learn more about population here:brainly.com/question/25630111

6 0

2 years ago

The radius of a large sphere is 8 times the radius of a small sphere. the surface area of the large sphere is how many times the

kondaur [170]

Large sphere's radius = R,
small sphere's radius = r, R = 8r
surface area of a sphere (SA) = 4×pi×radius^2
So what we need is the SA of the larger in terms of the smaller sphere, so if:
SA (of R) = 4×pi×R^2, then plug in "8r" for "R"...
SA = 4×pi×(8r)^2 = 4×3.14×64r^2
SA = 12.57×64r^2 = 804 r^2
Therefore the SA of the larger sphere is 804 times the SA of the smaller sphere.
I hope that makes sense!

8 0

3 years ago