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mojhsa [17]
3 years ago
6

Please help with algebra question

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
4 0
6x-y> = 5
 For this case what you should do is to graph the following straight line:
 6x-y = 5
 Then, the solution will be the shaded region that satisfies the following inequality:
 6x-y> = 5
 In the shaded region you will find all the solution points.
 Answer:
 
See attached image

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Tell whether the triangle with the given side lengths is a right triangle. 15, 35, 39 Yes or no<br>​
Lana71 [14]

Answer:

This would be a right triangle

Step-by-step explanation:

6 0
3 years ago
If A= (7,9) and B= (3,12) what is the length of AB?
MissTica
The length can be found using the Pythagorean Theorem...

c^2=a^2+b^2 and in this case:

d^2=(dx^2)+(dy^2)

d^2=(3-7)^2+(12-9)^2

d^2=-4^2+3^2

d^2=16+9

d^2=25

d=5 

So the length of AB=5 units.
8 0
4 years ago
Read 2 more answers
Can anyone help with this equation ?
Vaselesa [24]
Ahh good ole calculus. It’s been awhile. I think you plug in 9 for k and you should get 2(4)^9-1, which equals 2(4)^8. The only option would be your first.
5 0
3 years ago
Please help me this question​
san4es73 [151]

Answer: Choice D.  (x/8) - 2 = 5

Work Shown:

x = Aatif's age

x/8 = divide the age by 8

(x/8) - 2 = divide the age by 8 first, then subtract off 2

(x/8) - 2 = 5 .... the previous result is equal to 5

4 0
3 years ago
a ball is thrown with a slingshot at a velocity of 110ft/sec at an angle of 20 degrees above the ground from a height of 4.5 ft.
satela [25.4K]

Answer:

t=2.47\ s  

Step-by-step explanation:

The equation that models the height of the ball in feet as a function of time is

h(t) = h_0 + s_0t -16t ^ 2

Where h_0 is the initial height, s_0 is the initial velocity and t is the time in seconds.

We know that the initial height is:

h_0 = 4.5\ ft

The initial speed is:

s_0 = 110sin(20\°)\\\\s_0 = 37.62\ ft/s

So the equation is:

h (t) = 4.5 + 37.62t -16t ^ 2

The ball hits the ground when when h(t) = 0

So

4.5 + 37.62t -16t ^ 2 = 0

We use the quadratic formula to solve the equation for t

For a quadratic equation of the form

at^2 +bt + c

The quadratic formula is:

t=\frac{-b\±\sqrt{b^2 -4ac}}{2a}

In this case

a= -16\\\\b=37.62\\\\c=4.5

Therefore

t=\frac{-37.62\±\sqrt{(37.62)^2 -4(-16)(4.5)}}{2(-16)}

t_1=-0.114\ s\\\\t_2=2.47\ s  

We take the positive solution.

Finally the ball takes 2.47 seconds to touch the ground

4 0
4 years ago
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