<span>To do that, you need to set it all to zero and factor: x^2+8x+15 = 0 (x+5)(x+3) = 0 then put both those in parentheses chunks in their own equations x + 5 = 0 x + 3 = 0 and then simplify x = -5 x = -3 So the two points where the parabola crosses the x-axis are -5 and -3.</span>

3 0

3 years ago

What is 378×1234= please help

hram777 [196]

Using regular OLD math I get the answer...

466,452

3 0

3 years ago

Read 2 more answers

The volume of a cube can be calculated using the formula V = s^3, where s is the side length. What is the volume of a cube with

kumpel [21]

Answer:

Volume of a cube with side length 1/3 of a meter = 1/27m^3

Step-by-step explanation:

Let

1 meter = m

V = s^3

Where,

V= volume of a cube

s= side length

s = 1/3 of a meter

= 1/3 × m

= 1/3m

V = s^3

= 1/3^3

= 1/3m * 1/3m * 1/3m

V = 1/27m^3

Volume of a cube with side length 1/3 of a meter = 1/27m^3

3 0

3 years ago

Let R be the region in the first quadrant enclosed by the graph y=(square root(6x+4)), the line y=2x, and the y-axis. . . .Set u

kipiarov [429]

The two boundary curves y = √(6x + 4) and y = 2x meet at

√(6x + 4) = 2x

6x + 4 = 4x²

2x² - 3x - 2 = 0

(x - 2) (2x + 1) = 0

⇒ x = -1/2 and x = 2

R is bounded to the left by the y-axis (x = 0), so R is the set

R = {(x, y) : 0 ≤ x ≤ 2 and 2x ≤ y ≤ √(6x + 4)}

Using the shell method, the volume is made up of cylindrical shells of radius x and height √(6x + 4) - 2x. So each shell of thickness ∆x contributes a volume of

2π (radius) (height) ∆x = 2π x (√(6x + 4) - 2x) ∆x

and as we let ∆x approach zero, the total volume of the solid is given by the definite integral

$\displaystyle \boxed{2\pi \int_0^2 x \left(\sqrt{6x + 4} - 2x\right) \, dx}$

4 0

1 year ago