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DIA [1.3K]
3 years ago
5

Rewrite the function in intercept form y=x^2+8x+15

Mathematics
1 answer:
gavmur [86]3 years ago
3 0
<span>To do that, you need to set it all to zero and factor: x^2+8x+15 = 0 (x+5)(x+3) = 0 then put both those in parentheses chunks in their own equations x + 5 = 0 x + 3 = 0 and then simplify x = -5 x = -3 So the two points where the parabola crosses the x-axis are -5 and -3.</span>
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