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3 years ago

5

Rewrite the function in intercept form y=x^2+8x+15

1 answer:

gavmur [86]3 years ago

3 0

<span>To do that, you need to set it all to zero and factor: x^2+8x+15 = 0 (x+5)(x+3) = 0 then put both those in parentheses chunks in their own equations x + 5 = 0 x + 3 = 0 and then simplify x = -5 x = -3 So the two points where the parabola crosses the x-axis are -5 and -3.</span>

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Finding domain f(x)=3x+1/x-5

arlik [135]

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So $x-5 \neq 0 \\ 
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The domain is $x \neq 5$ .
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3 years ago

Answer the question above

Vera_Pavlovna [14]

Answer:

$tan\:\left(\frac{5\pi }{6}\right)=tan\left(-\frac{\pi }{6}\right)$

Option A is correct.

Step-by-step explanation:

We need to find equivalent of $tan\:\left(\frac{5\pi }{6}\right)$

First we solve $tan\:\left(\frac{5\pi }{6}\right)$

We get $-\frac{1}{\sqrt{3} }$

Now checking all the options.

Option A: $tan\:(-\frac{\pi}{6} )$

Solving $tan\left(-\frac{\pi }{6}\right)\: we\: get\: \mathbf{ -\frac{1}{\sqrt{3} }}$

Option B: $tan\left(\frac{7\pi }{6}\right)$

Solving $tan\left(\frac{7\pi }{6}\right)\: we\: get\: \mathbf{\frac{1}{\sqrt{3} }}$

Option C: $cot\left(\frac{5\pi }{6}\right)$

Solving $cot\left(\frac{5\pi }{6}\right)\:we\:get\:\mathbf{-\sqrt{3} }$

Option D : $tan\left(-\frac{5\pi }{6}\right)$

Solving $tan\left(-\frac{5\pi }{6}\right) \:we\:get:\mathbf{\frac{1}{\sqrt{3} } }$

So, looking at the options, only Option A has the same result as given question

So, $tan\:\left(\frac{5\pi }{6}\right)=tan\left(-\frac{\pi }{6}\right)$

Option A is correct.

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3 years ago

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kolezko [41]

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3 years ago

Read 2 more answers