Answer:
<h2>
$400</h2>
Step-by-step explanation:
Using the formula for calculating the simple interest expressed as;
Simple Interest = Principal * rate * time/100
Note that the principal is the amount he originally borrowed
I = PRT/100 ............ 1
Amount paid off A = Principal+Interest
A = P+I ............ 2
From equation 2; I = A-P......... 3
Substitute equation 3 into 1;
A-P = PRT/100
Given A = $440, R = 10%, Time = 1year
Substitute the given parameters into the resulting equation;
440 - P = P*10*1/100
440-P = 10P/100
440-P = 0.1P
440 = 0.1P+P
440 = 1.1P
Divide through by 1.1;
1.1P/1.1 = 440/1.1
P = $400
<em>Hence the amount Mr Noel originally borrow is $400</em>
F ( -1 ) = 2 · ( -1 )³ - 3 · ( -1 )² +7 =
= 2 · ( -1 ) - 3 · 1 + 7=
= - 2 - 3 + 7 = 2
The number of credit hours a student have to take for the two tuition costs to be equal is 2.5 hours. Option A
<h3>Equation</h3>
c(h) = 250 + 200h
s(h) = 300 + 180h
Where,
- number of credit hours taken = h
To have equal tuition in both schools,
equate both function
250 + 200h = 300 + 180h
200h - 180h = 300 - 250
20h = 50
h = 50/20
h = 2.5 hours.
The number of credit hours a student have to take for the two tuition costs to be equal is 2.5 hours.
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2 dollars is 17% converted
