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n200080 [17]
3 years ago
10

4x + 2y =10 4x -2y = -10 perpednicular or paralell

Mathematics
1 answer:
Alina [70]3 years ago
6 0

Answer:

the answer is perpendicular I think :)

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The quotient of any two integers is an intiger? True or false
Serggg [28]
The correct answer is true since an integer is simply just a number
4 0
3 years ago
Determine the solution to f(x) = g(x) using the following system of equations: (5 points) f(x) = 3x − 23 g(x) = −4.5x + 7
jeka94

Answer:

(The solution is (4, -11).

Step-by-stp explanation:

Let f(x) = g(x) = y:

y = 3x − 23

y = -4.5x + 7     Subtract the second equation from the first to eliminate y:

0 = 7.5x - 30

7.5x = 30

x = 4

Plug this into the first equation:

y = 3(4) - 23

y =  -11.

5 0
3 years ago
Two groups of staff at a store are making flowers to decorate the entrance. If Group A were to do it alone, it would take them 1
Tcecarenko [31]

Answer:

\dfrac{6750}{7}

Step-by-step explanation:

Let x be the number of flowers. If Group A were to make x flowers alone, it would take them 10 hours to complete the task, then they make \dfrac{x}{10} flowers in an hour.  If Group B were to make x flowers alone, it would take them 15 hours to complete the task, then they make \dfrac{x}{15} flowers in an hour.

The groups decided to work together. They can make \dfrac{x}{10}+\dfrac{x}{15}=\dfrac{x}{6} together in an hour and it takes them \dfrac{x}{\frac{x}{6}}=6 hours. Group B took a break for 1 hour and 40 minutes (1\dfrac{2}{3} hour), then Group B works

6-1\dfrac{2}{3}=4\dfrac{1}{3} hours.

Thus,

\dfrac{x}{10}\cdot 6-\dfrac{x}{15}\cdot 4\dfrac{1}{3}=300,\\ \\\dfrac{3x}{5}-\dfrac{13x}{45}=300,\\ \\14x=300\cdot 45=13500,\\ \\x=\dfrac{13500}{14}=\dfrac{6750}{7}.

6 0
3 years ago
I need help with this problem
Arada [10]

Answer:

65.56°

Step-by-step explanation:

We know that if we take dot product of two vectors then it is equal to the product of magnitudes of the vectors and cosine of the angle between them

That is let p and q be any two vectors and A be the angle between them

So, p·q=|p|*|q|*cosA

⇒cosA=\frac{u.v}{|u||v|}

Given u=-8i-3j and v=-8i+8j

|u|=\sqrt{(-8)^{2}+ (-3)^{2}} =8.544

|v|=\sqrt{(-8)^{2}+ (8)^{2}} =11.3137

let A be angle before u and v

therefore, cosA=\frac{u.v}{|u||v|}=\frac{(-8)*(-8)+(-3)*(8)}{8.544*11.3137} =\frac{40}{96.664}

⇒A=arccos(\frac{40}{96.664} )=arccos(0.4138 )=65.56

Therefore angle between u and v is 65.56°

5 0
3 years ago
Determine if the two lines y=2x-3/2 and y=-2x+2/3 are parallel, perpendicular or neither
8_murik_8 [283]
They’re both perpendicular, I used a graphing calculator to get the interpret answer
5 0
3 years ago
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