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Aloiza [94]
4 years ago
6

A classic counting problem is to determine the number of different ways that the letters of "embarrass""embarrass" can be arrang

ed. find that number
Mathematics
1 answer:
tamaranim1 [39]4 years ago
4 0
Total number of letters in word "embarrass" = 9
Following letters are repeated:
Letter a occurs 2 times
Letter r occurs 2 times
Letter s occurs 2 times

The number of different ways the letters of word embarrass can be arranged can be calculated using permutations. The total number of different ways the letters of "embarrass" can be arranged will be:

\frac{9!}{2!*2!*2!}=45360

Thus there are 45360 different ways to arrange the letters of the word embarrass. 
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The point of intersection of two given equations is (0.333, 2.667).

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So, the solution of 8x = 2x+2 will satisfy both equations.

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8(1) = 2(1)+2

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