What is 8(p+7+2q) simplified

Show and explain how replacing one equation by the sum of that equation and a multiple of the other produces a system with the s

My name is Ann [436]

First, let's multiply the first equation by two on the both sides:
8x + 7y = 39 /2
⇒ 16x + 14y = 78

Now, the system is:
16x + 14y = 78
4x – 14y = –68

After adding this up in the column:
(16x + 4x) + (14y - 14y) = 78 - 68
20x = 10
⇒ x = 10/20 = 1/2

y can be calculated by replacin the x:
8x + 7y = 39
⇒ 8 · 1/2 + 7y = 39
4 + 7y = 39
7y = 39 - 4
7y = 35
⇒ y = 35 ÷ 7 = 5

3 0

3 years ago

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Is 1:2:3 equivalent to 2:4:6

Finger [1]

Answer:

Yes it is.

Step-by-step explanation:

Just multiply everything by 2.

5 0

2 years ago

Drag the tiles to list the sides of △MNO from shortest to longest.

sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

MO/Shortest MO/Medium and MO/Longest

a) Friday

b) 70 minutes

c) 40%

d) Yes, the sum of the mean number of minutes spent on aerobic training and the mean number of minutes spent on strength training is equal to the mean total number of minutes spent training.

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= $\frac{}{MO}$

The next shortest side is the side opposite ∠M(61°) = $\frac{}{NO}$

The longest side is the side opposite ∠O(65°) = $\frac{}{MN}$

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on Friday

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = 70 minutes

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

$The$ $percentage$ $spent$ $on$ $strength$ $training$ = $\frac{120}{300}$ × $100 =$ $\frac{40}$ %

d) The mean number of minutes spent on strength training is found as follows;

$Mean_{strength} =\frac{120}{5} =24$

The mean number of minutes spent on aerobic training is found as follows;

$Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36$

$Mean_{strength} +Mean_{aerobic} =24+36=60$

The mean total number of minutes spent training, $Mean_{total}$ = $\frac{300}{5}$ = 60

Therefore;

$Mean_{strength}+Mean_{aerobic} = Mean_{total} \\$

Learn more here:

brainly.com/question/2962546

4 0

2 years ago

PLEASE HELP TIMED QUIZ

Karo-lina-s [1.5K]

Answer:

Randomly scattered meaning

D) A correlation of approximately 0

Hope this helps!

4 0

3 years ago

a shipping company charged $15 to ship a package and 5% to ensure the package what was total cost to ship this

postnew [5]

Answer:

15.75

Step-by-step explanation:

So we know 5% is 1/20 out of 100 (20x5=100) so then we need to set up the equation to find how much 5% of 15 is. Which is .75 cents. So we then add the 75 cents to the already $15 shipping fee to get an answer of 15 dollars and seventy five cents.

6 0

3 years ago

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