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Anit [1.1K]
2 years ago
15

Write 0.003 as the product of a whole number and a power of 10

Mathematics
1 answer:
Arte-miy333 [17]2 years ago
8 0

3 × 10^{-3}

expressing as a whole number, using the digits available, we obtain

3

Now consider the position of the decimal point in the original 0.003

To get it back to where it should be we require to move the decimal point 3 places to the left , denoted by a negative exponent

0.003 = 3 ×  10^{-3}


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If you had 6 5/7 and you have 3/4 away how much do u hav
Cerrena [4.2K]

Answer:

You have 5 27/28

Step-by-step explanation:

  1. 6 20/28 - 21/28= 5 27/28
  2. 5 27/28
7 0
3 years ago
Read 2 more answers
107=(9X-115) +(4x+27)​
Cloud [144]

Answer: x=15

Step-by-step explanation:

Equation: 107=(9x-115)+(4x+27)

Step 1: 9x+4x-115+27=107

Step 2: 13x-115+27=107

Step 3: 13x-88=107

Step 4: 13x-88+88=107+88

Step 5: 13x=195

Step 6: 13x/13=195/13

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6 0
2 years ago
Verify sine law by taking triangle in 4 quadrant<br>Explain with figure.<br>​
Ksivusya [100]

Proof of the Law of Sines

The Law of Sines states that for any triangle ABC, with sides a,b,c (see below)

a

 sin  A

=

b

 sin  B

=

c

 sin  C

For more see Law of Sines.

Acute triangles

Draw the altitude h from the vertex A of the triangle

From the definition of the sine function

 sin  B =

h

c

    a n d        sin  C =

h

b

or

h = c  sin  B     a n d       h = b  sin  C

Since they are both equal to h

c  sin  B = b  sin  C

Dividing through by sinB and then sinC

c

 sin  C

=

b

 sin  B

Repeat the above, this time with the altitude drawn from point B

Using a similar method it can be shown that in this case

c

 sin  C

=

a

 sin  A

Combining (4) and (5) :

a

 sin  A

=

b

 sin  B

=

c

 sin  C

- Q.E.D

Obtuse Triangles

The proof above requires that we draw two altitudes of the triangle. In the case of obtuse triangles, two of the altitudes are outside the triangle, so we need a slightly different proof. It uses one interior altitude as above, but also one exterior altitude.

First the interior altitude. This is the same as the proof for acute triangles above.

Draw the altitude h from the vertex A of the triangle

 sin  B =

h

c

      a n d          sin  C =

h

b

or

h = c  sin  B       a n d         h = b  sin  C

Since they are both equal to h

c  sin  B = b  sin  C

Dividing through by sinB and then sinC

c

 sin  C

=

b

 sin  B

Draw the second altitude h from B. This requires extending the side b:

The angles BAC and BAK are supplementary, so the sine of both are the same.

(see Supplementary angles trig identities)

Angle A is BAC, so

 sin  A =

h

c

or

h = c  sin  A

In the larger triangle CBK

 sin  C =

h

a

or

h = a  sin  C

From (6) and (7) since they are both equal to h

c  sin  A = a  sin  C

Dividing through by sinA then sinC:

a

 sin  A

=

c

 sin  C

Combining (4) and (9):

a

 sin  A

=

b

 sin  B

=

c

 sin  C

7 0
2 years ago
What is the y-intercept of the graph of the function f(x) = x2 + 3x + 5?
agasfer [191]

Answer:

(0,5)

Step-by-step explanation:

If you plug in 0 in all the variables of x, f(x)=0+0+5

We know that f(x) is y...so y=5, while x=0

7 0
3 years ago
Liz wants to estimate the percentage of people who rent their home. She surveys 320 individuals and finds that 176 rent their ho
SOVA2 [1]

Answer: 0.065

Step-by-step explanation:

Given : Sample size : n= 320

The sample proportion of people who rent their home : p=\dfrac{176}{320}=0.55

Significance level : \alpha:1-0.98=0.02

Then , Critical value : z_{\alpha/2}=2.33

The formula to find the margin of error : -

E=z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}\\\\\Rightarrow\ E=(2.33)\sqrt{\dfrac{0.55(1-0.55)}{320}}\\\\\Rightarrow\ E=0.064799034281\approx0.065

Hence, the margin of error for the confidence interval for the population proportion with a 98% confidence level =0.065

4 0
2 years ago
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