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2 years ago

Wouldn't it be -1 I keep getting me wrong answer

Mathematics

1 answer:

AVprozaik [17]2 years ago

6 0

Have u tryed 1 insted of -1 or it might be o solution

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A tangent and a secant x = ?

guajiro [1.7K]

x = 45°

Solution:

Given data:

Measure of larger arc = 152°

Measure of smaller arc = 62°

<em>If a tangent and a secant intersect at the exterior of a circle then the measure of angle formed is one-half the positive difference of the measures of the intercepted arcs.</em>

$$\Rightarrow x = \frac{1}{2}(\text{ larger arc }- \text{smaller arc} )$

$$\Rightarrow x = \frac{1}{2}(152^\circ-62^\circ)$

$$\Rightarrow x = \frac{1}{2}(90^\circ)$

⇒ x = 45°

The value of x is 45°.

8 0

3 years ago

Find the volume of the rectangular prism below. (Hint: Volume = Base Area x Height of Prism)

Inga [223]

Answer:

The answer is D

Step-by-step explanation:

Base area: 9 x 7 = 63

63 x 5 = 315

6 0

1 year ago

A roast turkey is taken from an oven when its temperature has reached 185 degrees F and is placed on a table in a room where the

Vedmedyk [2.9K]

(a) Using Newton's Law of Cooling, $\dfrac{dT}{dt} = k(T - T_s)$ , we have $\dfrac{dT}{dt} = k(T - 75)$ where T is temperature after T minutes.
Separate by dividing both sides by T - 75 to get $\dfrac{dT}{T - 75} = k dt$ . Integrate both sides to get $\ln|T - 75| = kt + C$ .

Since $T(0) = 185$ , we solve for C:
$|185 - 75| = k(0) + C\ \Rightarrow\ C = \ln 110$
So we get $\ln|T - 75| = kt + \ln 110$ . Use T(30) = 150 to solve for k:
$\ln| 150 - 75 | = 30k + \ln 110\ \Rightarrow\ \ln 75 - \ln 110= 30k \Rightarrow \\ k= \frac{1}{30}\ln (75/110) = \frac{1}{30}\ln(15/22)$

So

$\ln|T - 75| = kt + \ln 110 \Rightarrow |T - 75| = e^{kt + \ln110} \Rightarrow \\ \\
|T - 75| = 110e^{kt} \Rightarrow T - 75 = \pm110e^{(1/30)\ln(15/22)t} \Rightarrow \\
T = 75 \pm110e^{(1/30)\ln(15/22)t}$

But choose Positive because T > 75. Temp of turkey can't go under.

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} \\
T(45) = 75 + 110e^{(1/30)\ln(15/22)(45)} = 136.929 \approx 137{}^{\circ}F$

(b)

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} = 75 + 110(15/22)^{t/30} \\
100 = 75 + 110(15/22)^{t/30} \\
25 = 110(15/22)^{t/30} 
\frac{25}{110} = (15/22)^{t/30} \\
\ln(25/110) / ln(15/22) = t/30 \\
t = 30\ln(25/110) / ln(15/22) \approx 116\ \mathrm{min}$

Dogs of the AMS.

4 0

3 years ago

Ted’s team score average of 23.5 points in 4 basketball games. Lauren's team scores an average of 75.5 points in the same 4 gam

Setler [38]

Answer:

Lauren has 52 more points than Ted.

Step-by-step explanation:

Ted- 23.5

Lauren- 75.5

75.5-23.5=52

5 0

2 years ago

Help please!!! Best answer will get brainliest!!!

r-ruslan [8.4K]

Answer is b for this question

3 0

2 years ago