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-Dominant- [34]
3 years ago
10

Find the distance between (3,-6) and (2,-4). please help

Mathematics
1 answer:
Advocard [28]3 years ago
5 0

Answer:

\sqrt{99}

Step-by-step explanation:

you can use the distance formula to find the distance between two given points.

the distance formula is:

d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}

so if you simply plug in you get:

d = \sqrt{(2 - 3)^2 + (-4-(-6))^2}

simplify

d = \sqrt{(-1)^2 + (-10)^2}\\

simplify again

d = \sqrt{-1 + 100}\\

and again

d = \sqrt{99}\\

and you have an answer

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Softa [21]

Answer:

Step-by-step explanation:

f(x)  = 2x² + 14x - 4

= 2(x² + 7x) - 4

= 2(x² +7x + 3.5²) - 2(3.5²) - 4

= 2(x+3.5)² - 28.5

vertex (3.5, -28.5) = (7/2, -57/2)

The vertical intercept is the y-intercept, i.e., f(0) = -4.

The x-intercepts are the values of x for which y=0.

2x² + 14x - 4  = 0

x = [-14±√(14²-4(2)(-4))]/[2(2)] = [-7±√57]/2 ≅ -7.27, 0.27

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3 years ago
16d - (4 - 5d) = -67 Please help me find d
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3 years ago
Read 2 more answers
1 – 7k + 3k 2 + 10k + 7 – 5k 2
Katyanochek1 [597]

1) The variables are "k"

2) There are 4 terms

3) The coefficients are k

4) The constants are -7, 3, 10, -5

5) The like terms is -7k, 3k, 10k, -5k

The answers are pretty direct but, hope this answers your question.

Have a great day/night!

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Step-by-step explanation:

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