Question

Water flows at a rate of 9000 cubic inches per minute into a cylindrical tank. the tank has a diameter of 144 inches and a height of 72 inches. what is the height, in inches, of the water in the tank after 10 minutes? round your answer to the nearest tenth.

Answer 1

V = π*r^2*h
(9000 in^3/min)*(10 min) = π*(72 in)^2*h
h = (90,000 in^3)/(5184π in^2) ≈ 5.5 in

Answer 2

Answer:

5.5 inches

Step-by-step explanation:

Water flows at a rate of  9000 cubic inches per minute into a cylindrical tank.

In 1 minute = 9000 cubic inches

in 10 minute = 9000 × 10 = 90000 cubic inches

Diameter = 144 inches

Radius = 144/2 = 72 inches

Now the volume of the water filled in the cylindrical tank in 10 minutes = πr²h = 90000 cubic inches.

h = 90000/(πr²)

$h=\frac{90000}{(3.14).(72)^{2}}=90000/16277.76=5.5 inches$

Therefore the height of the water filled in tank after 10 minutes will be 5.5 inches.