Part of a cheerleading routine is throwing a flyer straight up and catching her on the way down. The flyer begins this move with
her center of gravity 4 feet above the ground. She is thrown with an initial vertical velocity of 30 feet per second.
2 answers:
The formula would be
y=4 + 30t -16t^2
Her maximum height is when the velocity is zero. so V = 30 -32t 0 = 30 -32t t=15/16 seconds.
What is the rest of the question?
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Step-by-step explanation:
CD: $X
Savings: $4X
Mutual: $(15,000-5X)
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