Question

Part of a cheerleading routine is throwing a flyer straight up and catching her on the way down. The flyer begins this move with her center of gravity 4 feet above the ground. She is thrown with an initial vertical velocity of 30 feet per second.

Answer 1

The formula would be
y=4 + 30t -16t^2
Her maximum height is when the velocity is zero.  so V = 30 -32t  0 = 30 -32t  t=15/16 seconds.

Answer 2

What is the rest of the question?