Well i think that if there is 25 ball there is more likely to be odd cause there is not 26 balls to make even and odds have the same amount of odd and even balls so there is one more odd than there is even
There are 13 odd numbers from 1-25. (13/25)*(12/24)= 13/50=0.26=26%
The probability of picking an odd number for the first ball is 13/25 (13 odds and 25 total). Without replacing, meaning there are only 24 left and suppose the first one is odd number, then you only have 12 odd number balls left. The probability of picking a ball thats an odd number is 12/24 (12 odds left and 24 total). You then multiply the two fractions to get the probability of both balls are odd numbers because they are dependent events (you multiply when events are dependent).
Using the Punnette Square : R r <span>R RR Rr </span> <span>r Rr rr </span>Hence, <span>By applying the rules of probability Rr x Rr, the probability of the offspring being homozygous recessive will be one fourth or a quarter. SO the best is :
