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jeyben [28]
2 years ago
12

8 1/8 i need help please

Mathematics
2 answers:
deff fn [24]2 years ago
8 0

Answer:

V=a^3

V=8 1/2^3

V=614.125

Step-by-step explanation:

Gnoma [55]2 years ago
6 0

Answer:

V=a^3

V=8 1/2^3

V=614.125

Step-by-step explanation:

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How do you solve for the central area of a polygon?
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Getting the central area of a polygon is not possible. Probably the question refers to the central angle. In a a regular polygon, getting the central angle is that you need to use the formula.

Central Angle of a polygon = 360 degrees / number of sides of a polygon.
Why 360 degrees? Because, a circle has a total of 360 degrees. And a circle is a polygon with no sides.
5 0
3 years ago
A circle has a radius of 3. An arc in this circle has a central angle of 20°. What is the length of the arc? Either enter an exa
Semenov [28]

Answer:

\frac{\pi  }{3}

2 * \pi * 3  * \frac{20}{360}

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Step-by-step explanation:

5 0
2 years ago
What does similar figures mean?
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5 0
3 years ago
In a class in which the final course grade depends entirely on the average of four equally weighted 100-point tests, Joyce has s
d1i1m1o1n [39]

Answer:

66 ≤ f ≤100

Explanation

Mean= ( Σ x ) / n

Mean= sum of scores/ number of subject she took

Now, she already too 3 subject which sum is 85+83+86=254

Now we need to know range of score for her to have (grade) a mark between 80 and 89

Now let take the lower limit mean=80

The lowest score she can get is

Mean = ( Σx) / n

80=(85+83+86+f)/4

80×4= 254+f

Therefore, f= 320-254=66

Therefore the minimum score she can have to have a B is 66.

Then, let take the upper limit mean 89. i.e the maximum she can have so that she don't have an A grade.

Mean = ( Σx) / n

89=( 83+85+86+f)/4

89×4= 254+f

f= 356-254

f=102.

Therefore this shows that she cannot have an A grade in the exam. The maximum score for the exam is 100.

There the range of score is 66 ≤ f ≤100 to have a B grade

66 ≤ f ≤100 answer

Since she cannot score 102 in the examination.

8 0
3 years ago
Please help with this...thank you:D
Crank
Relationship 1: y1 = x + 3
Relationship 2: y2 = 3x^2
Relationship 3: y3 = 3^x
6 0
3 years ago
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