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2 years ago

Using the rules for special cases, what is the result of?

Mathematics

2 answers:

Arlecino [84]2 years ago

8 0

Answer:

C) 4x^2 -8x +4[/tex]

Step-by-step explanation:

(-2x+2)^2

we apply (a+b)^2 formula

$(a+b)^2 = a^2 + 2ab +b^2$

a= -2x and b= 2

Replace 'a' with -2x and 'b' with 2

$(-2x+2)^2 = (-2x)^2 + 2(-2x)(2) +2^2$

(-2x)^2 is 4x^2

$(-2x+2)^2 = 4x^2 -8x +4$

option C is the answer

lakkis [162]2 years ago

5 0

Answer:

The correct answer is Option C 4x² -8x + 4

Step-by-step explanation:

(a + b)² = a² + 2ab + b²

Here a = -2x and b = 2

(-2x - 2)² = (-2x)² + 2*(-2x)*2 + 2²

(-2x - 2)² = 4x² -8x + 4

Therefore the correct answer is option C . 4x² -8x + 4

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Alenkasestr [34]

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1 year ago

For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of

Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is $(-1)^{k+1}(\frac{1}{2^{k}})$ .

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as $(-1)^{k+1}(\frac{1}{2^{k}})$ .

where k is from 1 to 10.

By the given expression sequence will be $\frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......$

In this sequence first term "a" = $\frac{1}{2}$

and common ratio in each successive term to the previous term is 'r' = $\frac{\frac{(-1)}{4}}{\frac{1}{2} }$

r = $-\frac{1}{2}$

Since the sequence is infinite and the formula to calculate the sum is represented by

$S=\frac{a}{1-r}$ [Here r is less than 1]

$S=\frac{\frac{1}{2} }{1+\frac{1}{2}}$

$S=\frac{\frac{1}{2}}{\frac{3}{2} }$

S = $\frac{1}{3}$

Now we are sure that the sum of infinite terms is $\frac{1}{3}$ .

Therefore, sum of 10 terms will not exceed $\frac{1}{3}$

Now sum of first two terms = $\frac{1}{2}-\frac{1}{4}=\frac{1}{4}$

Now we are sure that sum of first 10 terms lie between $\frac{1}{4}$ and $\frac{1}{3}$

Since $\frac{1}{2}>\frac{1}{3}$

Therefore, Sum of first 10 terms will lie between $\frac{1}{4}$ and $\frac{1}{2}$ .

Option D will be the answer.

3 0

3 years ago

Can someone help me ASAP

lianna [129]

Answer:

D. 1/5^15

Step-by-step explanation:

When an exponent is negative you need to get the reciprocal to make it positive.

3 0

2 years ago

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Micah was asked to add the following expressions: 3x2−x−9x2+3x+2+−2x2+2x+5x2+3x+2 First, he combined like terms in the numerator

shtirl [24]

Micah was asked to add the following expressions:

$\frac{3x^2-x-9}{x^2+3x+2} + \frac{-2x^2+2x+5}{x^2+3x+2}$

First, he combined like terms in the numerator and kept the common denominator

First step is correct. He added the like terms in the numerator, because the denominators are same.

$3x^2 -x -9 -2x^2+2x+5becomes x^2 +x -4$

So he got , $\frac{x^2+x-4}{x^2+3x+2}$

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If we have x^2 is multiplied with other terms at the top and bottom , then we can cancel out x^2.

So Micah added the expression incorrectly. Final answer is not correct.

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2 years ago

Y=16 when x=4 , determine y when x=8

Serga [27]

Y= 32 if x= 8, 2 times 16 is 32

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3 years ago

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