All three triangles are congruent by SAS
Answer:
175 is the answer
Step-by-step explanation:



To find the value of f(3) we need to follow the below steps :
Step 1 : First plot the graph of f(x)
Step 2 : We need to find f(3) or the function value at x = 3 therefore, in the graph locate the point (3,0)
Step 3 : Draw a line parallel to Y-axis passing through the point (3,0) .
Step 4 : Now there exists two cases :
If the drawn line do not intersect the graph of f(x), then no value of f(3) exists for the given function of x
If the drawn line intersects the graph, then the intersection point is marked and a line parallel to x - axis is drawn passing through that marked or intersection point. And the line where it intersects the y - axis is our required value of f(3).
If this is wrong than I guess I wasn't smart enough :)
<h3>
It is equivalent to 2a+2b</h3>
We use the distributive property.
Multiply the outer term 2 by each term inside ('a' and b)
2 times a = 2a
2 times b = 2b
We add those results to get 2a+2b. We cannot combine these terms as they are not like terms.