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3 years ago

Please help.... me on this question

Mathematics

1 answer:

Sonja [21]3 years ago

8 0

Answer:

a = 30 degrees; b = 60 degrees; and c = 105 degrees.

Step-by-step explanation:

Angle a and the 30 degree angle are vertical angles and thus are equal.

Since the interior angles of a triangle always add up to 180 degrees, 30 + b + 90 degrees = 180 degrees, so that b must be 60 degrees.

Angle c and the 75 degree angle are straight angles, and so their sum must be 180 degrees. Thus, c = 105 degrees.

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What is (m+1)(m+1) multiplied

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Apply the "FOIL" method here. (m+1)(m+1) = m^2 + 1m + 1m + 1, or m^2 + 2m + 1.

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3 years ago

An astronaut who weighs 95 kilograms on Earth weighs 15.8 kilograms on the Moon. How much would a person weigh on the Moon if th

shutvik [7]

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3 years ago

A woman is randomly selected from the 18-24 age group. For women of this group, systolic blood pressures (in mm Hg) are normally

dybincka [34]

Answer:

0.0274

Step-by-step explanation:

The mean is $\mu =114.8$ and the standard deviation is $\sigma =13.1.$

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7 0

3 years ago

Read 2 more answers

Solve for x on each of these questions please!

IgorLugansk [536]

Answer:

1. x = 10

2. x = 4

Step-by-step explanation:

I use the angle ABC method:

AB² + AC² = BC²

6² + 8² = x²

x = 10

AB² + AC² = BC²

3² + x² = 5²

x = 4

HOPE THIS HELPS AND HAVE A NICE DAY <3

5 0

2 years ago

A softball pitcher has a 0.675 probability of throwing a strike for each pitch and a 0.325 probability of throwing a ball. If th

Dafna11 [192]

Answer:

The probability that exactly 19 of them are strikes is 0.1504

Step-by-step explanation:

The binomial probability parameters given are;

The probability that the pitcher throwing a strike, p = 0.675

The probability that the pitcher throwing a ball. q = 0.325

The binomial probability is given as follows;

$p(x) = _{n}C_{x}\cdot p^{x}\cdot q^{1-x}$

Where:

x = Required probability

Therefore, the probability that the pitcher throws 19 strikes out of 29 pitches is found as follows;

The probability that exactly 19 of them are strikes is given as follows;

$\binom{29}{19}(0.675)^{19}0.325^{10} = \frac{29!}{19!\times 10!}\times (0.675)^{19}\times 0.325^{10} = 0.1504$

Hence the probability that exactly 19 of them are strikes = 0.1504

8 0

3 years ago