5.2g weighs more because A handful of paper clips is 5.2 grams. A handful of push pins is 500 centigram a. Which handful weighs more? So 1c equals .o1 grams so isn't it 5.2 g compared to .05 grams which then means the paper clips are heavier?
Six million, one hundred seventy-three thousand, two hundred fifty three
Answer:
I cannot not give the correct solution, need more context. How many children are there, how many adults are in the family? So I will explain in my explanation.
Step-by-step explanation:
If more context were given, for example:<em> 2 adults and 2 children.</em>
Then the bakers would have bought 2 adult tickets for ___ each
Then the bakers would have bought 3 children's tickets for ___ each
So using what we know we can create an equation:
<em>2A+3C=28</em>,<em> </em>
meaning 2 adult tickets plus 3 children's tickets costs a total of $28.
So we divide 28 by 5, which is the total amount of tickets.
28/5=5.6
So to figure the cost of children's tickets multiply the cost by amount.
3*$5.6=$16.8, C=16.8
To figure out the cost of the adults tickets multiple the cost by the amount.
2*$5.6=$11.2, A=11.2
a) the bakers would have bought <u>2</u> adult tickets for <u>5.6</u> each.
b) the bakers would have bought <u>3</u> children's tickets for <u>5.6</u> each.
Answer:
2.275%
Step-by-step explanation:
The first thing to do here is to calculate the z-score
Mathematically;
z-score = (x-mean)/SD
from the question, x = 12,300 hours , mean = 11,500 hours while Standard deviation(SD) = 400 hours
Plugging the values we have;
z-score = (12,300-11,500)/400 = 800/400 = 2
Now, we want to calculate P(z ≤ 2)
This is so because we are calculating within a particular value
To calculate this, we use the z-score table.
Mathematically;
P(z ≤ 2) = 1 - P(z > 2) = 1 - 0.97725 = 0.02275
To percentage = 2.275%
Answer:
(arranged from top to bottom)
System #3, where x=6
System #1, where x=4
System #7, where x=3
System #5, where x=2
System #2, where x=1
Step-by-step explanation:
System #1: x=4
To solve, start by isolating your first equation for y.
Now, plug this value of y into your second equation.
System #2: x=1
Isolate your second equation for y.
Plug this value of y into your first equation.
System #3: x=6
Isolate your first equation for y.
Plug this value of y into your second equation.
System #4: all real numbers (not included in your diagram)
Plug your value of y into your second equation.
<em>all real numbers are solutions</em>
System #5: x=2
Isolate your second equation for y.
Plug in your value of y to your first equation.
System #6: no solution (not included in your diagram)
Isolate your first equation for y.
Plug your value of y into your second equation.
<em>no solution</em>
System #7: x=3
Plug your value of y into your second equation.
