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Lemur [1.5K]
3 years ago
13

Please help me I will give brainlist

Mathematics
1 answer:
grigory [225]3 years ago
8 0

Answer:

please send the whole question.

actually the value of f(x) is missing

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the perimeter of a rectangle is 34inches. the width of the rectangle is 5 inches. What is the length of the rectangle?
Juliette [100K]
The length is 12 inches long
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3 years ago
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Two lighthouses are located 20 miles from one another on a north-south line. If a boat is spotted S 25o E from the northern ligh
mafiozo [28]

Answer:

The southern lighthouse is 3.4 miles closer than the northern lighthouse

Step-by-step explanation:

From the figure we see that we need to find the distances AK and BK.

The measure of the third angle K is = 180- 25-35= 120 degrees

Using the sine ratios we can find the two distances

From the figure

The northern distance is given by

20/ sin 120 = kA/ sine 35

KA= 20 sine 35/ sine 120

KA= 13.25 miles

The southern distance is given by

20 /sine 120= KB / sine 25

20 sine 25/ sine 120 = KB

KB= 9.759=9.76 miles

Difference between the two miles =

13.25 miles - 9.76 miles = 3.49 miles

The southern lighthouse is 3.4 miles closer than the northern lighthouse

Option C is correct

7 0
3 years ago
What is the volume of the empty part of the box? Plz plz plz help
kodGreya [7K]

One third of the box will be 3 inches long, so is equivalent to a 3-inch cube. It has a volume of

... (3 in)³ = 27 in³

The appropriate choice is ...

... D. 27 cu. in.

_____

Volume is found by multiplying length by width by height. When all are the same (3 in), the product is (3 in)·(3 in)·(3 in) = (3 in)³.

6 0
3 years ago
Find x when : 3x^3 - 2x +1 = 0
notsponge [240]
Answer:  x = "-1 " ;  <u>and</u>:  "(1 ± √3) / 2" .
____________________________________________
Explanation:
____________________________________________
Given:  3x³ −  2x  + 1 = 0 ;  Find "x" ; 

Factor:  "3x³ −  2x + 1"  ;

3x³ − 2x + 1 = (3x² <span>− 3x + 1)(x + 1) ;

Now, set the equation equal to "0" (zero);

</span> (3x² − 3x + 1)(x + 1) = 0 ;

x = 0  ; when:
__________________________________
(x + 1) = 0 ;  and/or: when:

(3x² − 3x + 1) = 0 ;
__________________________________

Start with "x + 1 = 0" ;

Subtract "1" from each side of the equation ; to isolate "x" on one side of the <span>equation ; and</span> to solve for "x" ; 

              x + 1 − 1 = 0 − 1 ; 

                x = -1 ;

_______________________________
Now, try:  

3x² − 3x + 1 = 0 ;

Since:  "3x² − 3x + 1 " cannot be factored; and since:

  "3x² − 3x + 1 = 0" ; is written in the "quadratic equation format"; that is:

  "ax² + bx + c = 0 ;  a ≠ 0;  We can use the "quadratic equation formula" to solve for "x" ;  

in which "a = 3" ;   
              "b = -3" ;
              "c = 1" ;
     
The quadratic equation formula is:
__________________________________

x = [-b ± √(b²−4ac] / 2a ;

   = ?  (Let us plug in our known values for "a, b, & c"l 

x = { [-(-3] ± [√[(-3²) − (4*3*1)] } / {2* 3} ;

x = [3 ± √(9 − 12)] / 6 

x = [3 ± √(-3 )] / 6 ; 

x = (1 ± √3) / 2 .
<span>__________________________________________________
So, the answers are:  x = " -1 " ;  and:  "</span>(1 ± √3) / 2 " .
__________________________________________________
8 0
3 years ago
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