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liraira [26]
3 years ago
11

HELP// On a piece of paper, use a protractor to construct a triangle with angle measures of 20° and 30°.

Mathematics
1 answer:
jekas [21]3 years ago
3 0
Add the two angles together  then subtract 180 to find the third angle which equals 130 degrees so you have all your angles now you need the definitions for acute, obtuse, and right angle

right angle has a 90 degree angle so that cant be it

<span>an acute angle is less than 90 degrees so that is not it
</span>
obtuse angle is larger than 90 degrees so that must be the correct answer.. the correct answer is obtuse
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Let g(x)=Intragal from 0 to x f(t) dt, where r is the function whos graph is shown.
leonid [27]

If

\displaystyle g(x) = \int_0^x f(t) \, dt

then g(x) gives the signed area under f(x) over a given interval starting at 0.

In particular,

\displaystyle g(0) = \int_0^0 f(t) \, dt = 0

since the integral of any function over a single point is zero;

\displaystyle g(4) = \int_0^4 f(t) \, dt = 8

since the area under f(x) over the interval [0, 4] is a right triangle with length and height 4, hence area 1/2 • 4 • 4 = 8;

\displaystyle g(8) = \int_0^8 f(t) \, dt = 0

since the area over [4, 8] is the same as the area over [0, 4], but on the opposite side of the t-axis;

\displaystyle g(12) = \int_0^{12} f(t) \, dt = -8

since the area over [8, 12] is the same as over [4, 8], but doesn't get canceled;

\displaystyle g(16) = \int_0^{16} f(t) \, dt = 0

since the area over [12, 16] is the same as over [0, 4], and all together these four triangle areas cancel to zero;

\displaystyle g(20) = \int_0^{20} f(t) \, dt = 24

since the area over [16, 20] is a trapezoid with "bases" 4 and 8, and "height" 4, hence area (4 + 8)/2 • 4 = 24;

\displaystyle g(24) = \int_0^{24} f(t) \, dt = 64

since the area over [20, 24] is yet another trapezoid, but with bases 8 and 12, and height 4, hence area (8 + 12)/2 • 4 = 40, which we add to the previous area.

5 0
3 years ago
Given that f(x) = x2 + 6x – 2, g(x) = x – 7, and h(x) = x + 4 find each function.
choli [55]

Answer:

A) x² + 7x - 9

Step-by-step explanation:

Deduct\Add each like-term to arrive at your answer.

3 0
3 years ago
A jewelry store sells necklaces in lengths that vary from 16 inches to 22 inches. Any necklaces outside of this criteria are rej
Art [367]

Answer:

16-22

Step-by-step explanation:

3 0
3 years ago
The diameter of a circular tablecloth is 72 inches. Find the area and circumference. Use 3.14 as an approximation for pi.
nalin [4]

Answer:

Part 1) The area is A=4,069.44\ in^{2}

Part 2) The circumference is C=226.08\ in

Step-by-step explanation:

step 1

Find the area

we know that

The area of a circle (circular tablecloth) is equal to

A=\pi r^{2}

we have

r=72/2=36\ in ------> the radius is half the diameter

\pi =3.14

substitute

A=(3.14)(36)^{2}

A=4,069.44\ in^{2}

step 2

Find the circumference

we know that

The circumference of a circle (circular tablecloth) is equal to

C=\pi D

we have

D=72\ in

\pi =3.14

substitute

C=(3.14)(72)

C=226.08\ in

5 0
3 years ago
Write a quadratic function in vertex form whose graph has the vertex (-3,5) and passes through the point (0,-14)
dsp73

Answer:

f(x) = -19/9(x + 3)² + 5

Step-by-step explanation:

Given the vertex, (-3, 5) and the point, (0, 14):

Use the following quadratic equation formula in vertex form:

f(x) = a(x - h)² + k

where:

(h, k) = vertex

a = determines whether the graph opens up or down, and makes the graph wide or narrow.

<em>h</em><em> </em>= determines how far left or right the parent function is translated.

<em>k</em> =  determines how far up or down the parent function is translated.

Plug in the values of the vertex, (-3, 5) and the given point, (0, 14) to solve for <em>a</em>:

f(x) = a(x - h)² + k

14 = a(0 + 3)² + 5

14 = a(3)² + 5

14 = a(9) + 5

Subtract 5 from both sides:

-14 - 5 = 9a

-19 = 9a

Divide both sides by 9 to solve for a:

-19/9 = 9a/9

-19/9 = a

Therefore, the quadratic function in vertex form is:

f(x) = -19/9(x + 3)² + 5

Please mark my answers as the Brainliest, if you find this helpful :)

5 0
2 years ago
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