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statuscvo [17]
3 years ago
11

Solve for b.

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
7 0
C I think I solved it and that's what I got.
Andrew [12]3 years ago
4 0
You divide -1/3 on both sides and it equals -3... B i hope this helps
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On a recent homework assignment, Eli needed to solve the equation
tamaranim1 [39]

Answer:

A - the real answer is 7

Step-by-step explanation:

g²=49 (square root 49 to get 7)

B) not sure - possibly wrote the negative sign as a mistake

7 0
3 years ago
Hey! Can someone check my answers?
Andrew [12]
The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
</span>
20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}
Since x^{a}* x^{b}  =x^{a+b}, then x^{9}= x^{3}* x^{6}

Back to our expression:
4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+  5y ^{6}*1=5 y^{6} (4y ^{3} +1)
The greatest common factor is thus 5 y^{6}


Q2. The answer is <span>D. 12xy^2
</span>
12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}
We will use the rule  x^{a}* x^{b} =x^{a+b} to factorise the exponents:
12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)
The greatest common factor is thus 12xy^{2}
3 0
3 years ago
&lt;RQT is a straight angle. What are m&lt;RQS and m&lt;TQS​
never [62]

Answers:

  • x = 11
  • angle RQS = 106 degrees
  • angle SQT = 74 degrees

===========================================================

Explanation:

Straight angles are always 180 degrees in measure.

The two smaller angles shown add up to 180

(angle RQS) + (angle SQT) = angle RQT

(9x+7) + (6x+8) = 180

(9x+6x) + (7+8) = 180

15x+15 = 180

15x = 180-15

15x = 165

x = 165/15

x = 11

From here, we then know that,

  • angle RQS = 9x+7 = 9*11+7 = 99+7 = 106 degrees
  • angle SQT = 6x+8 = 6*11+8 = 66+8 = 74 degrees

Note how the two results add to 106+74 = 180 to help confirm the answers.

8 0
3 years ago
Numbers that add to -0.5 and multiply to 1
Oliga [24]
Short Answer
There are two numbers
x1 = -0.25 + 0.9682i   <<<< answer 1
x2 = - 0.25 - 0.9582i   <<<< answer 2 
 
I take it there are two such numbers.
Let one number = x
Let one number = y

x + y = -0.5    
y = - 0.5 - x       (1)
xy = 1               (2)

Put equation 1 into equation 2
xy = 1
x(-0.5 - x) = 1
-0.5x - x^2 = 1               Subtract 1 from both sides.
-0.5x - x^2 - 1 = 0          Order these by powers
-x^2 - 0.5x -1 = 0           Multiply though by - 1
x^2 + 0.5x + 1 = 0         Use the quadratic formula to solve this.

\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a}

a = 1
b = 0.5
c = 1


\text{x = }\dfrac{ -0.5 \pm \sqrt{0.5^{2} - 4*1*1 } }{2*1}

x = [-0.5 +/- sqrt(0.25 - 4)] / 2
x = [-0.5 +/- sqrt(-3.75)] / 2
x = [-0.25 +/- 0.9682i

x1 = -0.25 + 0.9682 i
x2 = -0.25 - 0.9682 i

These two are conjugates. They will add  as x1 + x2 = -0.25 - 0.25 = - 0.50.

The complex parts cancel out.  Getting them to multiply to 1 will be a little more difficult. I'll do that under the check.

Check
(-0.25 - 0.9682i)(-0.25 + 0.9682i)
Use FOIL
F:-0.25 * -0.25 = 0.0625
O: -0.25*0.9682i
I: +0.25*0.9682i
L: -0.9682i*0.9682i = - 0.9375 i^2 = 0.9375

Notice
The two middle terms (labled "O" and "I" ) cancel out. They are of opposite signs.

The final result is 0.9375 and 0.0625 add up to 1
 
7 0
3 years ago
Ella has 50stacks of ten pennies how many pennies ella has in all?
dedylja [7]

Ella has 500 pennies.

7 0
3 years ago
Read 2 more answers
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