How many real number solutions are there to the equation 0=-3x^2 + x -4
1 answer:
We have that
<span>the equation
y=-3x</span>²<span> + x -4
the </span><span>real number solutions are the points x intercept of the graph
are the points when y=0
using a graph tool
see the attached figure
</span><span>the graph has no point of intersection with the x axis
</span>therefore
the answer is
there are zero real numbers solutions
<span>the equation
y=-3x</span>²<span> + x -4
the </span><span>real number solutions are the points x intercept of the graph
are the points when y=0
using a graph tool
see the attached figure
</span><span>the graph has no point of intersection with the x axis
</span>therefore
the answer is
there are zero real numbers solutions
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Answer:
p =
Step-by-step explanation:
q=- r÷ t using BODMAS
q = - (r/t)
q + r/t =
p=