You can solve for the velocity and position functions by integrating using the fundamental theorem of calculus:
<em>a(t)</em> = 40 ft/s²
<em>v(t)</em> = <em>v </em>(0) + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
<em>v(t)</em> = -20 ft/s + ∫₀ᵗ (40 ft/s²) d<em>u</em>
<em>v(t)</em> = -20 ft/s + (40 ft/s²) <em>t</em>
<em />
<em>s(t)</em> = <em>s </em>(0) + ∫₀ᵗ <em>v(u)</em> d<em>u</em>
<em>s(t)</em> = 10 ft + ∫₀ᵗ (-20 ft/s + (40 ft/s²) <em>u</em> ) d<em>u</em>
<em>s(t)</em> = 10 ft + (-20 ft/s) <em>t</em> + 1/2 (40 ft/s²) <em>t</em> ²
<em>s(t)</em> = 10 ft - (20 ft/s) <em>t</em> + (20 ft/s²) <em>t</em> ²
<h3>
Answer: 80 degrees</h3>
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Explanation:
Angle 3 and the 100 degree angle are corresponding angles. They are both in the southeast quadrant of their four-corner angle configuration. Assuming the lines that look horizontal are parallel, this would mean angle 3 is 100 degrees. Recall that corresponding angles are congruent when we have parallel lines.
Once we know that angle 3 = 100, we will use this to find angle 4.
Angles 3 and 4 add to 180. They form a straight angle or straight line.
(angle3)+(angle4) = 180
(100) + (angle4) = 180
angle4 = 180-100
angle4 = 80 degrees
Answer: -1
Step-by-step explanation:
slope formula: y=mx+b
m=slope
y=(-1)x+8
Answer:
The only answer that would work would be D) | 4.8 - ( -2.3) |
Step-by-step explanation:
This is because the distance is the absolute value of the difference of the two numbers. B and C would also work, but the 2.3 is not negative. A does not work because it is addition.