Ask question

Ask question

All categories

3 years ago

15

3. Assume all angles are right angles. What is the area of the figure? 12 m 8 m 10 m 16 m 12 m 12 m 1536 square meters b. 408 sq

uare meters C. 360 square meters d. 102 square meters

1 answer:

Svetach [21]3 years ago

3 0

C. 360 Square meters

........

You might be interested in

Is 52 right??? This is my 4th post

Snezhnost [94]

Answer:

Yes I think so

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The sum of two and three times the difference of a number and five is equal to four times the difference a number and one.

Andru [333]

Answer:

$x=-9$

Step-by-step explanation:

We translate the phrase into an equation:

$2+3(x-5)=4(x-1)\\$

Then we simplify:

$2+3(x-5)=4(x-1)\\2+3x-15=4x-4\\-13+3x=4x-4\\-9=x$

4 0

2 years ago

Hi pls help thank you

miss Akunina [59]

Answer:

it would be c when fully simplified.

6 0

2 years ago

Read 2 more answers

Please answer hurry!!!!

lutik1710 [3]

The best way to solve this problem is by plugging in each answer choice for both equations and seeing which one works. You can already see that choice A doesn't work because -1 is not greater than or equal to 4. That means you just need to test choices B and C!

Choice B (4, -2)
$x + y \geq 6\\
4 + -2 \geq 6\\
2 \geq 6 
$
2 is not greater than or equal to 6, so choice B doesn't work.

Choice C (4, 2)
$x + y \geq 6\\ 
4 + 2 \geq 6\\ 
6 \geq 6 \\\\
x \geq 4\\
4 \geq 4$
Since 6 is equal to 6 and 4 is equal to 4, choice C works!

-------

Answer: C) (4, 2)

6 0

2 years ago

Scores on a university exam are Normally distributed with a mean of 78 and a standard deviation of 8. The professor teaching the

mafiozo [28]

Answer:

Porcentage of students score below 62 is close to 0,08%

Step-by-step explanation:

The rule

68-95-99.7

establishes:

The intervals:

[ μ₀ - 0,5σ , μ₀ + 0,5σ] contains 68.3 % of all the values of the population

[ μ₀ - σ , μ₀ + σ] contains 95.4 % of all the values of the population

[ μ₀ - 1,5σ , μ₀ + 1,5σ] contains 99.7 % of all the values of the population

In our case such intervals become

[ μ₀ - 0,5σ , μ₀ + 0,5σ] ⇒ [ 78 - (0,5)*8 , 78 + (0,5)*8 ] ⇒[ 74 , 82]

[ μ₀ - σ , μ₀ + σ] ⇒ [ 78 - 8 , 78 +8 ] ⇒ [ 70 , 86 ]

[ μ₀ - 1,5σ , μ₀ + 1,5 σ] ⇒ [ 78 - 12 , 78 + 12 ] ⇒ [ 66 , 90 ]

Therefore the last interval

[ μ₀ - 1,5σ , μ₀ + 1,5 σ] ⇒ [ 66 , 90 ]

has as lower limit 66 and contains 99.7 % of population, according to that the porcentage of students score below 62 is very small, minor than 0,15 %

100 - 99,7 = 0,3 %

Only 0,3 % of population is out of μ₀ ± 1,5 σ, and by symmetry 0,3 /2 = 0,15 % is below the lower limit, 62 is even far from 66 so we can estimate, that the porcentage of students score below 62 is under 0,08 %

6 0

2 years ago