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riadik2000 [5.3K]
3 years ago
15

Find the angle(s) of rotation that will carry a 12 sided polygon onto itself.

Mathematics
1 answer:
Reptile [31]3 years ago
6 0
There are 2 ways of looking at this problem:

1. Mathematical
2. Logical

Personally, I think #2 is the most efficient way of answering:

When you think about it, in order to complete a full rotation, an object must rotate 360°. 

Therefore in order for a 12-sided polygon to rotate onto itself, the angle of rotation is 360°.

Hope this helps!
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Step-by-step explanation:

When somethin is decreasing you would subtract the percent it was decreasing by, by 1.

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Please help me ASAP. This is for Trigonometry, Math
Rufina [12.5K]

Answer:  C) exactly one triangle

<u>Step-by-step explanation:</u>

Given: ∠A = 45°, ∠B = 65°, side c = 4 cm

By the Triangle Sum Theorem, ∠C = 70°

Now you have a proportion so you can use the Law of Sines to find the exact length of side a and of side b.

\dfrac{\sin\angle A}{a}=\dfrac{\sin\angle B}{b}=\dfrac{\sin\angle C}{c}\\\\\\\dfrac{\sin 45^o}{a}=\dfrac{\sin65^o}{b}=\dfrac{\sin70^o}{4}

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5 0
3 years ago
A report indicated that 37% of adults had received a bogus email intended to steal personal information. Suppose a random sample
fiasKO [112]

Answer:

5.05% probability that no more than 34% had received such an email.

Step-by-step explanation:

We use the binomial approximation to the normal to solve this problem.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 700, p = 0.37

\mu = E(X) = np = 700*0.37 = 259

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{700*0.37*0.63} = 12.77

In a random sample of 700 adults, what is the probability that no more than 34% had received such an email?

34% is 0.34*700 = 238

So this probability is the pvalue of Z when X = 238.

Z = \frac{X - \mu}{\sigma}

Z = \frac{238 - 259}{12.77}

Z = -1.64

Z = -1.64 has a pvalue of 0.0505

5.05% probability that no more than 34% had received such an email.

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Blababa [14]

Answer:

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Step-by-step explanation:

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