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dimulka [17.4K]
3 years ago
9

-6k+7k how do I solve this

Mathematics
2 answers:
nadya68 [22]3 years ago
7 0

Answer:

-k

Step-by-step explanation:

  1. It's like saying what is 7-6
  2. so the answer is -k or -1k
emmainna [20.7K]3 years ago
6 0

Answer: k

Step-by-step explanation: Since there isn’t any replacement for k, think of that expression as -6+7. -6+7 is 1. 1k is basically k so the answer is k.

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The point (x,y) is proportional to the point (2, 5).
Anna [14]

Answer:

Help

Step-by-step explanation:

3 0
3 years ago
A prism is filled with 44 cubes with 1/2 units side lengths. What is the volume of the prism in cubic units?
Tanzania [10]
The volume would be 5.5 cubic units.

First, we need to find the volume of one cube. It would be LWH.
0.5 x 0.5 x 0.5 = 0.125

Now, just multiply that volume by 44.
0.125 x 44 = 5.5
8 0
3 years ago
During the first hour of operation the farm stand owner sold 15% of the apples he had. On the second hour he sold 20% of the rem
liraira [26]

Answer:

 3.825 kg apples.

Step-by-step explanation:

Let x kg be the amount of apples stand owner had initially.

We have been given that during the first hour of operation the farm stand owner sold 15% of the apples he had. Then the amount of sold apples will be:

\text{The amount of sold apples during 1st hour}=\frac{15}{100}x=0.15x

\text{The amount of remaining apples after 1st hour}=x-0.15x

\text{The amount of remaining apples after 1st hour}=0.85x

On the second hour he sold 20% of the remaining apples. So the amount of sold apples on the second hour will be 20% of 0.85x.

\text{The amount of sold apples during 2nd hour}=0.85x*\frac{20}{100}  

\text{The amount of sold apples during 2nd hour}=0.85x\times 0.20  

\text{The amount of sold apples during 2nd hour}=0.17x

During the second hour 25.5 kg of apples were sold, so we can set up an equation as:

25.5=0.17x

\frac{25.5}{0.17}=\frac{0.17x}{0.17}

150=x

So, stand owner had initially 150 kg of apples.

\text{The amount of remaining apples after 2nd hour}=0.85x-0.17x

\text{The amount of remaining apples after 2nd hour}=0.68x

On the third hour he sold 25% of the remaining apples. So the amount of sold apples on the 3rd hour will be 25% of 0.68x

\text{The amount of sold apples during 3rd hour}=0.68x*\frac{25}{100}

\text{The amount of sold apples during 3rd hour}=0.68x*0.25

\text{The amount of sold apples during 3rd hour}=0.17x  

\text{The amount of remaining apples after 3rd hour}=0.68x-0.17x

\text{The amount of remaining apples after 3rd hour}=0.51x

As remaining apples were sold 5% more each following hour.

\text{The amount of sold apples during 4th hour}=0.51x*\frac{5}{100}

\text{The amount of sold apples during 4th hour}=0.51x*0.05

\text{The amount of sold apples during 4th hour}=0.0255x

Let us substitute x=150 into above equation we will get,

\text{The amount of sold apples during 4th hour}=0.0255*150

\text{The amount of sold apples during 4th hour}=3.825

Therefore, 3.825 kg of apples were sold during the 4th hour.

7 0
2 years ago
Valeria drives 500 meters up a hill that makes an angle of 15 degrees with the horizontal. To the nearest tenth of a meter, what
s344n2d4d5 [400]

Answer:

Approximately 485 meters

Step-by-step explanation:

We can first construct a right triangle, using the 500 m length of hill as our hypotenuse. Using the fact that the cosine of an angle is the ratio of the adjacent side to the hypotenuse, we see that

\cos{15^\circ}=\frac{x}{500}

where x is the horizontal distance covered. Solving for x, we find this horizontal distance to be

x=500\cos{15^\circ}\approx500(0.97)=485

so our answer is approximately 485 m.

4 0
2 years ago
How can you find 4 x 754 using two different methods
xxMikexx [17]

Partial products and  multiplication

6 0
3 years ago
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