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3 years ago

A triangle with three 60° angles is always a/an _______________ triangle.

1 answer:

7 0

It’s called an equilateral triangle because all sides are even. A triangle equals 180 degrees. So, 60 degrees x 3 sides = 180 degrees

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Can you find the midpoint of AB

Masteriza [31]

Use the distance formula for the 2 points and then halve the answer

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3 years ago

Read 2 more answers

I have a ribbon 5/7 of a foot. I want to cut it in 5/12 pieces. How many pieces can I cut 5/7 divided by 5/12= 5/7 x5/12= 15/7 p

Otrada [13]

100 cm = 1 meter
4.5 meter x 100 cm = 450 cm 

450 cm / 4.5 cm = number of pieces of ribbon 

450/4.5 = 100

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3 years ago

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

$v=\frac{d}{t}$ .

Applying this to our problem we have that

$v=\frac{200m}{6.509s}= 30.726m/s$ .

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that $v=\frac{d}{t}$ . This formula implies that

$t=\frac{d}{v}$ .

First, observer that $19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s$ .

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, $v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.$

Then, applying 1) we have that

$t=\frac{200m}{36.003m/s}=5.5549s.$

So, Sam Whittingham’s time through the 200 m was 5.5549s.

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3 years ago

After 2 days, the Johnsons had used

salantis [7]

Answer:

11.5 tanks of gas

Step-by-step explanation:

23/2

11.5

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4 years ago

How to find mean average diviation

Ilia_Sergeevich [38]

To find the mean absolute deviation of the data, start by finding the mean of the data set.Find the sum of the data values, and divide the sum by the number of data values.Find the absolute value of the difference between each data value and the mean: ...Find the sum of the absolute values of the differences.

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3 years ago