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3 years ago

I need help! Help a 6th Grader out! Please Asap!

Mathematics

1 answer:

natali 33 [55]3 years ago

5 0

There isn’t no question to answer

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?! if you make $360 a week what is your yearly wage ?

yKpoI14uk [10]

Answer:

18,720

Step-by-step explanation:

there are approximately 52 weeks in a year

7 0

3 years ago

Read 2 more answers

I need help with math please

Dennis_Churaev [7]

Answer:

47/30

Step-by-step explanation:

2.35 * 2/3 =

= 2 35/100 * 2/3

= 2 7/20 * 2/3

= 47/20 * 2/3

= 94/60

= 47/30

5 0

2 years ago

s the number of points scored during a basketball gamenumber of points scored during a basketball game a discrete random variab

Temka [501]

Answer:

The answer is Discrete Random Variable

Step-by-step explanation:

A random variable is considered discrete if its possible values are countable.

In our case,

In a basketball game, for example, it is only possible for a team's score to be a whole number—no fractions or decimals are allowed, and so the score is discrete.

A good rule of thumb is this: if the variable you're measuring has to be rounded before it's written down, then it's continuous. If no rounding is necessary, as with anything that's countable, then it's discrete.

5 0

2 years ago

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Is x - 8 a factor of the function f(x) = -2x3 + 17x2 - 64? Explain.

Oduvanchick [21]

we know that

If $(x-8)$ is a factor of the function $f(x)=-2x^{3}+17x^{2}-64$

then

$x=8$ is a root of the function f(x)

therefore

For $x=8$ the value of the function must be zero

Verify

Substitute the value of $x=8$ in the function

$f(8)=-2(8)^{3}+17(8)^{2}-64$

$f(8)=-2(512)+17(64)-64$

$f(8)=-1,024+1,088-64$

$f(8)=-1,088+1,088$

$f(8)=0$

therefore

<u>the answer is</u>

Yes, $(x-8)$ is a factor of the function f(x)

7 0

3 years ago

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Suppose n(x)= 22 and n(y) is 13 what is the maximum number of elements X ∪Y can have ?

Nikolay [14]

The inclusion/exclusion principle states that

$|X\cup Y|=|X|+|Y|-|X\cap Y|$

That is, the union has as many members as the sum of the number of members of the individual sets, minus the number of elements contained in both sets (to avoid double-counting).

Therefore, $|X\cup Y|$ will have the most elements when the sets $X$ and $Y$ are disjoint, i.e. $X\cap Y=\emptyset$ , which would mean the most we can can in this case would be

$|X\cup Y|=|X|+|Y|=22+13=35$

(Note that $n(X)=|X|$ denotes the cardinality of the set $X$ .)

3 0

3 years ago