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Sveta_85 [38]
3 years ago
13

I need help! Help a 6th Grader out! Please Asap!

Mathematics
1 answer:
natali 33 [55]3 years ago
5 0

There isn’t no question to answer

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Which point is a solution to the system of equations?<br> y = 2x + 2<br> Y = 3x
Kay [80]

Answer:

(2,6)

Step-by-step explanation:

y = 2x + 2

Y = 3x

2x+2=3x

2x-3x+2=0

-x+2=0

-x=-2

x=2

y=3(2)=6

                           

7 0
2 years ago
WILL GIVE BRAINLIEST!! PLEASE ANSWER ASAP
krok68 [10]
My answer would be (0,5) because that seems to be where this scatter plot starts.

Hope this helps!
7 0
2 years ago
Exercises<br>Determine the point of Intersection of the two lines.<br>y= x + 3<br>y= 2x + 1​
GuDViN [60]

Answer:

(2,5)

Step-by-step explanation:

5 0
3 years ago
Water is being pumped into a 12-foot-tall cylindrical tank at a constant rate.
Stels [109]

Answer:

4 feet

Step-by-step explanation:

It is given that:

• At 2:30 p.m., the water depth was 2.6 feet.  

• It is now 5:00 p.m., and the depth of the water is 3.6 feet.

So in 2.5 hours ( 5pm - 2:30pm) the water rose 1 feet (3.6 - 2.6).

Now <em><u>we can find how much water rises in 1 hour by setting up a ratio (let x be the depth increase of water in 1 hr):</u></em>

\frac{2.5}{1}=\frac{1}{x}\\2.5x=1*1\\2.5x=1\\x=\frac{1}{2.5}\\x=0.4

So, in 1 hour, the water level will rise 0.4 feet

So, at 6pm (1 hour from 5 pm) it will rise to 3.6 + 0.4 = 4 feet

8 0
3 years ago
What is the surface area of this rectangular pyramid?
Alexxx [7]

Answer:

304m^2

Step-by-step explanation:

First find the surface area of the base by multiplying the length by the width.

(12m) (8m)= 96m^2

Second, find the surface area of the front and back triangles using the formula <em>1/2 (base) (height)</em>. Use the length for the base.

1/2 (12m) (10m)= 60m^2

Next, find the surface area of the side triangles using the formula <em>1/2 (base) (height). </em>Use the width as the base.

1/2 (8m) (11m)= 44m^2

Last, add the surface area of each section. Make sure you add the area of each face.(we only solved for 1 of the front/ back triangles and 1 of the side triangles) To make it easier to understand I wrote out an equation to show how I added the surface areas.

base=a, front/ back triangles= b, side triangles=c

SA= a + 2b +2c  or SA= a +b +b +c +c

Using one of the equations above solve for the total surface area.

SA= (96m^2) + (60m^2) +(60m^2) +(44m^2) +(44m^2)

or

SA= (96m^2) + 2(60m^2) +2(44m^2)

SA=  (96m^2) +(120m^2) +(88m^2)

SA= 304m^2

7 0
3 years ago
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