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3 years ago

If the endpoints of the diameter of a circle are (−10, −8) and (−6, −2), what is the standard form equation of the circle?

2 answers:

7 0

First, find the midpoint of the diameter. the midpoint is the center of the circle.
[(-10+(-6)]/2=-8, [(-8+(-2)]/2=-5
so the center is at (-8, -5)
next, find the distance between the two points:
d=√[-6-(-10)]²+[-2-(-8)]²=√4²+6²=√52=2√13
half of the diameter is radius, r=half of 2√13=√13
standard equation for the circle is (x-h)²+(y-k)²=r², (h,k) being the center, r the radius
(x+8)²+(y+5)²=13 is the answer.

Mekhanik [1.2K]3 years ago

3 0

Answer:

(x + 8)2 + (y + 5)2 = 13

Step-by-step explanation:

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2 years ago

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earnstyle [38]

Answer:

A. 84 pi feet^2

Step-by-step explanation:

So the lateral area is the rectangular piece on the net

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Therefore the radi, area, circumference ect.. are the same.

So the only missing measurement we need to find the lateral area is the length of the rectangular piece

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