The expected value of the game is $2.00.
To Find: The fair price to pay to play the game of rolling a colored die with three red sides, two green sides, and one blue side
Now the question arises how to find the Fair Price
We are told that in the game of rolling the colored die;
A roll of a red loses.
A roll of blue pays 5.00 and A roll of green pays 2.00.
Now, the best game to get the fairest price is to play; RRRGGB i.e (RED, RED, RED, GREEN, GREEN,BLUE)
Fair price = 2(3/6) + 6(1/6) + 0(2/6)
Fair price = $2
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Answer:
y= 3/7x− 3/26
Step-by-step explanation:
I don’t understand your question
Answer:
66
Step-by-step explanation:
B is 57
C is 57
180 - (57 x 2) =
180 - 114 = 66
Answer:
Therefore,
The area of the rectangle in terms of width
![Area=W^{2}+2W](https://tex.z-dn.net/?f=Area%3DW%5E%7B2%7D%2B2W)
Step-by-step explanation:
Let the Width of rectangle be 'W' inches.
The length of a rectangle be 'L' inches.
According to the given condition,
Length = 2 + Width
![L = W + 2](https://tex.z-dn.net/?f=L%20%3D%20W%20%2B%202)
To Find:
Area of Rectangle in terms of Width = ?
Solution:
We have area of rectangle given as
![\textrm{Area of Rectangle}=Length\times Width](https://tex.z-dn.net/?f=%5Ctextrm%7BArea%20of%20Rectangle%7D%3DLength%5Ctimes%20Width)
Substituting the values we get
![Area=(W+2)\times W](https://tex.z-dn.net/?f=Area%3D%28W%2B2%29%5Ctimes%20W)
Applying Distributive property A(B+C)=AB+ACwe get
.......As required
Therefore,
The area of the rectangle in terms of width
![Area=W^{2}+2W](https://tex.z-dn.net/?f=Area%3DW%5E%7B2%7D%2B2W)