Left side: (equation) 2/x=3/90 (multiply them together by cross multiplying. 90x2 divided by 3)
=60
Altogether: 90 (right) + 60 (left) =150 seats in total
Angle bisector would be the answer
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
If we call the number "x" then:
x*25%=21
x*25/100=21
x=21*4
x=84
What is the interquartile range of this data set?<br>
2,5,9,11,18, 30, 42, 48, 55, 73, 81
Lubov Fominskaja [6]
Answer:
46
Step-by-step explanation:
55-9=46
2=min
9=Lq
30=median
55= Uq
81= max
