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3 years ago

Help for brianilist! first answer will get brianilist!!!!!!!

Mathematics

1 answer:

stealth61 [152]3 years ago

7 0

HI THERE!!!!!

The answer is your question is the second choice 59 in^2.

Here is how you can do it:

1. Area of rectangle = length*width = 7*4 = 28 square inches
2. Area of triangle on the top = 0.5*base*height = 0.5*7*6 = 21 square inches
3. Area of triangle on right side = 0.5*base*height = 0.5*4*5 = 10 square inches.

Now you can do the total area:
Add them all →→ 28+21+10 = 59

Hope this helps u out.;)P.S. id really appreciate brainliest thx

~ TRUE BOSS

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Evaluate each expression when a = -4 and b = 3 1.) ab 2.) 2a + 3b 2.) 2(a - b)

Svet_ta [14]

1) -12

ab is a times b. We plug in the numbers (-4)*(3) which equals -12.

2) 1

We plug in -4 for a, and 3 for b into the equation.

We get 2(-4) + 3(3)

2*-4 is -8. 3*3 is 9. We add them both, and -8+9 equals 1.

3) -14

We plug in -4 for a, and 3 for b into the equation.

2(-4-3)

-4-3 is -7. -7*2 equals -14.

3 0

3 years ago

Solve for d 1.2+d+0.4=9.7

mote1985 [20]

1.2+d+0.4=9.7
1.6+d=9.7
-1.6. -1.6

D=8.1

5 0

3 years ago

Use the method of lagrange multipliers to find

Yanka [14]

Answer:

a) The function is: f(x, y) = x + y.

The constraint is: x*y = 196.

Remember that we must write the constraint as:

g(x, y) = x*y - 196 = 0

Then we have:

L(x, y, λ) = f(x, y) + λ*g(x, y)

L(x, y, λ) = x + y + λ*(x*y - 196)

Now, let's compute the partial derivations, those must be zero.

dL/dx = λ*y + 1

dL/dy = λ*x + 1

dL/dλ = (x*y - 196)

Those must be equal to zero, then we have a system of equations:

λ*y + 1 = 0

λ*x + 1 = 0

(x*y - 196) = 0

Let's solve this, in the first equation we can isolate λ to get:

λ = -1/y

Now we can replace this in the second equation and get;

-x/y + 1 = 0

Now let's isolate x.

x = y

Now we can replace this in the last equation, and we will get:

(x*x - 196) = 0

x^2 = 196

x = √196 = 14

then the minimum will be:

x + y = x + x = 14 + 14 = 28.

b) Now we have:

f(x) = x*y

g(x) = x + y - 196

Let's do the same as before:

L(x, y, λ) = f(x, y) + λ*g(x, y)

L(x, y, λ) = x*y + λ*(x + y - 196)

Now let's do the derivations:

dL/dx = y + λ

dL/dy = x + λ

dL/dλ = x + y - 196

Now we have the system of equations:

y + λ = 0

x + λ = 0

x + y - 196 = 0

To solve it, we can isolate lambda in the first equation to get:

λ = -y

Now we can replace this in the second equation:

x - y = 0

Now we can isolate x:

x = y

now we can replace that in the last equation

y + y - 196 = 0

2*y - 196 = 0

2*y = 196

y = 196/2 = 98

The maximum will be:

x*y = y*y = 98*98 = 9,604

6 0

3 years ago

I surveyed students in my Math II classes to see how many hours of television they watched the night before our big test on tria

Oduvanchick [21]

Given the table below representing the number of hours of television nine Math II class students watched the night before a big test on triangles along with the grades they each earned on that test.

$\begin{center}
\begin{tabular}
{|c|c|}
Hours Spent Watching TV & Grade on Test (out of 100) \\ [1ex]
4 & 71 \\ 
2 & 81 \\ 
4 & 62 \\ 
1 & 86 \\ 
3 & 77 \\ 
1 & 93 \\ 
2 & 84 \\ 
3 & 80 \\ 
2 & 85
\end{tabular}
\end{center}$

Let the number the number of hours of television each of the students watched the night before the test be x while the grades they each earned on that test be y.

We use the following table to find the equation of the line of best fit of the regression analysis of the data.

$\begin{center} \begin{tabular} {|c|c|c|c|} x & y & x^2 & xy \\ [1ex] 4 & 71 & 16 & 284 \\ 2 & 81 & 4 & 162 \\ 4 & 62 & 16 & 248 \\ 1 & 86 & 1 & 86 \\ 3 & 77 & 9 & 231 \\ 1 & 93 & 1 & 93 \\ 2 & 84 & 4 & 168 \\ 3 & 80 & 9 & 240 \\ 2 & 85 & 4 & 170 \\ [1ex]\Sigma x=22 & \Sigma y=719 & \Sigma x^2=64 & \Sigma xy=1,682 \end{tabular} \end{center}$

Recall that the equation of the line of best fit of a regression analysis is given by
$y=a+bx$
where:
$a= \frac{(\Sigma y)(\Sigma x^2)-(\Sigma x)(\Sigma xy)}{n(\Sigma x^2)-(\Sigma x)^2}$
and
$b= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{n(\Sigma x^2)-(\Sigma x)^2}$

$y=\frac{(719)(64)-(22)(1,682)}{9(64)-(22)^2}+\frac{9(1,682)-(22)(719)}{9(64)-(22)^2}x \\ \\ = \frac{46,016-37,004}{576-484} + \frac{15,138-15,818}{576-484} x \\ \\ = \frac{9,012}{92} + \frac{-680}{92} x \\ \\ =97.95-7.391x$

Thus, the equation of the line of best fit is given by y = 97.95 - 7.391x

A student that watched 1.5 hours of TV will have a score given by
y = 97.95 - 7.391(1.5) = 97.95 - 11.0865 = 86.8635

Therefore, a student’s score if he/she watched 1.5 hours of TV to the nearest whole number is 87.

6 0

3 years ago

What is <img src="https://tex.z-dn.net/?f=%20-%20%20%5Csqrt%7B36%7D%20" id="TexFormula1" title=" - \sqrt{36} " alt=" - \sq

Crazy boy [7]

$-\sqrt{36}=-6\ \text{because}\ -6^2=-36$

6 0

3 years ago