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lyudmila [28]
3 years ago
15

Create a procedure that generates a random string of length L , containing all capital letters. The procedure, CreateRandomStrin

g, receives the length of the string (L) in EAX, and returns the pointer to a byte array in ESI held the random string. Part 2 Write a driver program uses the CreateRandomString procedure to generate 20 random strings. Each random string with a random length between 1~100. Output all strings in the console window.
Computers and Technology
1 answer:
Rina8888 [55]3 years ago
4 0

Answer:

google it

Explanation:

google is smart like birb

You might be interested in
Complete function PrintPopcornTime(), with int parameter bagOunces, and void return type. If bagOunces is less than 3, print "To
SVETLANKA909090 [29]

Answer:

<h2>Function 1:</h2>

#include <stdio.h> //for using input output functions

// start of the function PrintPopcornTime body having integer variable //bagOunces as parameter

void PrintPopcornTime(int bagOunces){

if (bagOunces < 3){ //if value of bagOunces is less than 3

 printf("Too small"); //displays Too small message in output

 printf("\n"); } //prints a new line

//the following else if part will execute when the above IF condition evaluates to //false and the value of bagOunces is greater than 10

else if (bagOunces > 10){

    printf("Too large"); //displays the message:  Too large in output

    printf("\n"); //prints a new line }

/*the following else  part will execute when the above If and else if conditions evaluate to false and the value of bagOunces is neither less than 3 nor greater than 10 */

else {

/* The following three commented statements can be used to store the value of bagOunces * 6 into result variable and then print statement to print the value of result. The other option is to use one print statement printf("%d",bagOunces * 6) instead */

    //int result;

    //result = bagOunces * 6;

    //printf("%d",result);

 printf("%d",bagOunces * 6);  /multiplies value of bagOunces  to 6

 printf(" seconds");

// seconds is followed with the value of bagOunces * 6

 printf("\n"); }} //prints a new line

int main(){ //start of main() function body

int userOunces; //declares integer variable userOunces

scanf("%d", &userOunces); //reads input value of userOunces

PrintPopcornTime(userOunces);

//calls PrintPopcornTime function passing the value in userOunces

return 0; }

Explanation:

<h2>Function 2:  </h2>

#include <stdio.h> //header file to use input output functions

// start of the function PrintShampooInstructions body having integer variable numCycles as parameter

void PrintShampooInstructions(int numCycles){

if(numCycles < 1){

//if conditions checks value of numCycles is less than 1 or not

printf("Too few."); //prints Too few in output if the above condition is true

printf("\n"); } //prints a new line

//else if part is executed when the if condition is false and else if  checks //value of numCycles is greater than 4 or not

else if(numCycles > 4){

//prints Too many in output if the above condition is true

printf("Too many.");

printf("\n"); } //prints a new line

//else part is executed when the if and else if conditions are false

else{

//prints "N: Lather and rinse." numCycles times, where N is the cycle //number, followed by Done

for(int N = 1; N <= numCycles; N++){

printf("%d",N);

printf(": Lather and rinse. \n");}

printf("Done.");

printf("\n");} }

int main() //start of the main() function body

{    int userCycles; //declares integer variable userCycles

   scanf("%d", &userCycles); //reads the input value into userCycles

   PrintShampooInstructions(userCycles);

//calls PrintShampooInstructions function passing the value in userCycles

   return 0;}

I will explain the for loop used in PrintShampooInstructions() function. The loop has a variableN  which is initialized to 1. The loop checks if the value of N is less than or equal to the value of numCycles. Lets say the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 1<2. So the program control enters the body of loop. The loop body has following statements. printf("%d",N); prints the value of N followed by

printf(": Lather and rinse. \n"); which is followed by printf("Done.");

So at first iteration:

printf("%d",N); prints 1 as the value of N is 1

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

1: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 2.

Now at second iteration:

The loop checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 2=2. So the program control enters the body of loop.

printf("Done."); prints Done after the above two lines.

printf("%d",N); prints 2 as the value of N is 2

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

2: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 3.

The loop again checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to false as N<numCycles  which means 3>2. So the loop breaks.

Now the next statement is:

printf("Done."); which prints Done on the screen.

So as a whole the following output is displayed on the screen:

1: Lather and rinse.

2: Lather and rinse.

Done.

The programs along with their outputs are attached.

6 0
3 years ago
Which is the best and quickest way for Jim to share his scuba experience with everyone?
iren [92.7K]
Option B

Blog is the best way
7 0
4 years ago
Primary memory consists of the various devices that are able to store data and programs even when the power is off. true or fals
balu736 [363]

Answer: I think its true but I'm not like 100% sure sorry

Explanation: i dont know just seems right

6 0
3 years ago
Write about storage<br>(should be in easy words)​
enyata [817]

Answer:

Answer to the following question is as follows;

Explanation:

The process of storing digital information in a data storage media using computing technology is known as storage. Storage is a technique that allows a computer to keep data indefinitely or intermittently. Computer storage capacity and electronic data management are other terms for storage.

6 0
3 years ago
// This pseudocode segment is intended to compute the number
Harlamova29_29 [7]

DEBUG01-01

//This pseudocode is intended to describe

//computing the price of an item on sale for 10% off

START

  input origPrice

  discount = origPrice * 0.10

  finalPrice = origPrice - discount

  output finalPrice

STOP

DEBUG01-02

//This pseudocode is intended to compute the number

//of miles per gallon you get with your automobile.

START

  input milesTraveled

  input gallonsOfGasUsed

  milesPerGallon = milesTraveled / gallonsOfGasUsed

     //milesPerGallon is computed using division

  output milesPerGallon

     //miles is misspelled, and the P in milesPerGallon should be uppercase

STOP

  //Program should end with stop

DEBUG01-03

//This pseudocode is intended to describe

//computing the per day cost of your rent

//in a 30-day month

START

  input rent

  costPerDay = rent / 30

     // Comment indicates 30-day month

  output costPerDay

     // output should be costPerDay

STOP

<h3>What is an algorithm?</h3>

An algorithm can be defined as a standard formula which comprises a set of finite steps and instructions that must be executed by a software program, in order to proffer solutions to a problem on a computer, under appropriate conditions.

         

<h3>What is a pseudocode?</h3>

A pseudocode can be defined as a description of the steps that are contained in an algorithm, especially through the use of a plain (natural) language.

<u>Note:</u> The indentation may change due to Brainly's text editor.

Read more on pseudocode here: brainly.com/question/13208346

#SPJ1

<u>Complete Question:</u>

Your downloadable files for Chapter 1 include DEBUG01-01.txt, DEBUG01-02.txt, and DEBUG01-03.txt. Each file starts with some comments (lines that begin with two slashes) that describe the program. Examine the pseudocode that follows the introductory comments, then find and correct all the bugs.

4 0
2 years ago
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