Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
Answer:
The answer is A(-3,-4) B(-1,2) C(2,1) D(0,-5)
Step-by-step explanation:
well it would be 18/9 and that would simplify to 2 because if u divide both by 9 u get 2/1 which is 2
Answer:
3/5
Step-by-step explanation:
y2 - y1 / x2 - x1
-1 - (-4) / 2 - (-3)
3/5
3/5 is the slope.