Answer: 11
The code would print 11 as x=x-4 basically sets x to what x was and subtracts it by 4 which means 15 was its previous value and it takes 4 away from it so it is now 11. Then because the loop condition is x=11 the loop condition has been met and will now go and display x.
Answer:
d = √5 ≈ 2.24
Step-by-step explanation:
B is located at (1, 3) and B' is located at (3, 4)
Distance formula:
[tex] d = \sqrt{(xB' - xB)^2 + (yB' - yB)^2}[\tex]
replacing with the coordinates of the points:
[tex] d = \sqrt{(3 - 1)^2 + (4 - 3)^2}[\tex]
[tex] d = \sqrt{4 + 1}[\tex]
d = √5 ≈ 2.24
Answer:
for my answer i got 512 but it is not one of the answer choices
Step-by-step explanation:
The answer is 12.1
Have a nice day
Answer:
... There isnt answer choices...
