Answer:636
Step-by-step explanation: I just kno
Answer:
x=17
Step-by-step explanation:
Answer: Infinite solutions.
![\bf 2sec^2(\theta )-tan(\theta )-3=0 \\\\\\ 2[1+tan^2(\theta )]-tan(\theta )-3=0\implies 2+2tan^2(\theta )-tan(\theta )-3=0 \\\\\\ 2tan^2(\theta )-tan(\theta )-1=0\implies [2tan(\theta )+1][tan(\theta )-1]=0\\\\ -------------------------------\\\\](https://tex.z-dn.net/?f=%5Cbf%202sec%5E2%28%5Ctheta%20%29-tan%28%5Ctheta%20%29-3%3D0%0A%5C%5C%5C%5C%5C%5C%0A2%5B1%2Btan%5E2%28%5Ctheta%20%29%5D-tan%28%5Ctheta%20%29-3%3D0%5Cimplies%202%2B2tan%5E2%28%5Ctheta%20%29-tan%28%5Ctheta%20%29-3%3D0%0A%5C%5C%5C%5C%5C%5C%0A2tan%5E2%28%5Ctheta%20%29-tan%28%5Ctheta%20%29-1%3D0%5Cimplies%20%5B2tan%28%5Ctheta%20%29%2B1%5D%5Btan%28%5Ctheta%20%29-1%5D%3D0%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C)


bear in mind that tangent is sine/cosine or y/x
for the tangent to be negative, the signs of "y" and "x" must differ, and that happens only on the II and IV quadrants
and for the tangent to be positive, the signs must be same, and that's only on I and III quadrants.