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hichkok12 [17]
3 years ago
5

Type the correct answer in each box. The equation of the line in this graph is y = x + .

Mathematics
1 answer:
Naddik [55]3 years ago
6 0

Answer:

y = \frac{3}{2} x + 3

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c (m is the slope and c the y-intercept )

to calculate m use the gradient formula

y = (y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (0, 3)

m = \frac{3-0}{0+2} = \frac{3}{2}

the line crosses the y-axis at (0, 3) ⇒ c = 3

y = \frac{3}{2} x + 3


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Suppose f(x)= 2 ^ x - 3x and g(x = 1 - 2x. Find each of the following functions. a. (f + g)(x) b. (f- g)(x)
bearhunter [10]

Answer:

(f+g)(x)=2^x-5x+1 and

(f-g)(x)=2^x-x-1

Step-by-step explanation:

(f+g)(x)=2^x-3x+1-2x

=2^x-5x+1

(f-g)(x)=2^x-3x-1+2x2x

=2^x-x-1

6 0
3 years ago
If x= 1/2-√3 , prove that x³-2x²-7x+5=3
prohojiy [21]
x=\frac{1}{2}-\sqrt3\\\\x^3-2x^2-7x+5=3\\\\(\frac{1}{2}-\sqrt3)^3-2(\frac{1}{2}-\sqrt3)^2-7(\frac{1}{2}-\sqrt3)+5\\\\=(\frac{1}{2})^3-3\cdot(\frac{1}{2})^2\cdto\sqrt3+3\cdot\frac{1}{2}\cdot(\sqrt3)^2-(\sqrt3)^3-...\\\\...-2[(\frac{1}{2})^2-2\cdot\frac{1}{2}\cdot\sqrt3+(\sqrt3)^2]-\frac{7}{2}+7\sqrt3+5

=\frac{1}{8}-\frac{3\sqrt3}{4}+\frac{9}{2}-3\sqrt3-2(\frac{1}{4}-\sqrt3+3)-\frac{7}{2}+7\sqrt3+5\\\\=\frac{1}{8}+\frac{9}{2}-\frac{1}{2}-6-\frac{7}{2}+5-\frac{3}{4}\sqrt3-3\sqrt3+2\sqrt3+7\sqrt3\\\\=\frac{1}{8}+\frac{1}{2}-1+5\frac{1}{4}\sqrt3=\frac{1}{8}-\frac{1}{2}+5\frac{1}{4}\sqrt3=\frac{1}{8}-\frac{4}{8}+5\frac{1}{4}\sqrt3\\\\=-\frac{3}{8}+5\frac{1}{4}\sqrt3\neq3
6 0
2 years ago
Kareem purchased several packs of gum to place in gift baskets for $1.26 each. He spent a total of $8.82. How many packs of gum
777dan777 [17]

Answer: 7 packs of gum.

Step-by-step explanation:

If the total amount of the purchase is $8.82 and the individual price is $1.26, to find out how many packs Kareem purchased, we need to divide the total amount spent ($8.82) by the amount of each pack ($1.26), so:

8.82 ÷ 1.26 = 7

So, Kareem bought 7 packs of gum.

5 0
3 years ago
25 pts plz help!!!!!!!!!!!
alexdok [17]
Which part needs answering ?
3 0
2 years ago
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This is true, because there is an infinite amount of real numbers in both, and they are both countably infinite (so these infinities are equal). Hope this helps!
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3 years ago
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