Answer:
The answer (2, 1), (-4,13), (6,-7)
Step-by-step explanation:
Consider 2x+y=5 as equation 1, and 3y=15-6x as equation 2
1. Substituting values x and y with x=2 and y=1 as given by the coordinates (2,1)
Equation 1
2(2)+1=5 therefor it holds
Equation 2
3(1)=15-(6×2) also holds
2. Substituting values x and y with x=6 and y=-7 as given by the coordinates (6,-7)
Equation 1
2(6)+(-7)=5
5=5 holds
Equation 2
3(-7)=15-(6×6)
-21=-21 also holds
3. Substituting values x and y with x=-4 and y=13 as given by the coordinates (-4,13)
Equation 1
2(-4)+13=13-8=5 holds
Equation 2
3(13)=15-(6×-4)=39 also holds
4. Substituting values x and y with x=-2 and y=-9 as given by the coordinates (-2,-9)
Equation 1
2(-2)+(-9)=-4-9=-13≠5 does not hold
Equation 2
3(-9)≠15-(6×-2)
-27≠27 does not hold
The coordinates (2,1), (-4,13) and (6,-7) can be used as solutions to the system given
![\sqrt[4]{ x^{3} } = x^{3/4}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%20x%5E%7B3%7D%20%7D%20%3D%20x%5E%7B3%2F4%7D%20)
![\sqrt[10]{ x^{5} * x^{4}* x^{2} } = \sqrt[10]{ x^{11} }= x^{11/10}](https://tex.z-dn.net/?f=%20%5Csqrt%5B10%5D%7B%20x%5E%7B5%7D%20%2A%20x%5E%7B4%7D%2A%20x%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%5B10%5D%7B%20x%5E%7B11%7D%20%7D%3D%20x%5E%7B11%2F10%7D%20%20)
