All categories

2 years ago

Can someone find the area of the sidewalk?

Mathematics

1 answer:

Artyom0805 [142]2 years ago

6 0

You need to find the area of the total rectangle, and subtract the area of the green rectangle from it. Therefore the solution is 12x10 - 8x6. This equals 72; part (C) of the question.

Therefore the solution is 72 units square; part (C).

You might be interested in

What is 33 1/3 of 12?

worty [1.4K]

It is around 400, if u see the world “of” is usually means multiply :)

6 0

3 years ago

ABCD has a perimeter of 27 units and is dilated by a scale factor of 1/3. What is the perimeter of A¹B¹C¹D¹?

Alex17521 [72]

Answer:

Perimeter of A'B'C'D' = 9 units

Step-by-step explanation:

Given:

Perimeter of ABCD = 27 units

Scale factor = 1 / 3

Find:

Perimeter of A'B'C'D'

Computation:

Perimeter of A'B'C'D' = 1/3[Perimeter of ABCD]

Perimeter of A'B'C'D' = 1/3[27]

Perimeter of A'B'C'D' = 9 units

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20-%20x%20%5E%7B3%7D%20%7D%20" id="TexFormula1" title=" \sqrt{ - x ^{3} } " alt=

noname [10]

I'm guessing you're given the function $y(x)=2-x^3$ , and you're asked to find the inverse function $y^{-1}(x)$ . To do this, swap $x$ and $y$ , then solve for $y$ :

$x=2-y^3\implies y^3=2-x\implies y=(2-x)^{1/3}=\sqrt[3]{2-x}$

so that the inverse function is

$y^{-1}(x)=\sqrt[3]{2-x}$

Just to verify:

$y(y^{-1}(x))=y(\sqrt[3]{2-x})=2-(\sqrt[3]{2-x})^3=2-(2-x)=x$

$y^{-1}(y(x))=y^{-1}(2-x^3)=\sqrt[3]{2-(2-x^3)}=\sqrt[3]{x^3}=x$

But in case you're actually only interested in computing the square root, first we note that $\sqrt x$ (the real-valued square root) is only defined as long as $x\ge0$ . So $\sqrt{-x^3}$ is defined as long as $-x^3\ge0$ , or $x^3\le0$ , or equivalently $x\le0$ . Under this condition, we could write

$\sqrt{-x^3}=\sqrt{-x\times x^2}=\sqrt{-x}\sqrt{x^2}$

We can simplify this further, but we have to be careful. Suppose $x=-1$ . Then $x^2=(-1)^2=1$ . But we get the same result if $x=1$ , since $x^2=1^2=1$ . There are two possible values of $x$ that given the same value of $x^2$ , so to capture both of them, we take $\sqrt{x^2}=|x|$ , the absolute value of $x$ . Then

$\sqrt{-x^3}=|x|\sqrt{-x}$

We can't simplify the square root term further than this.

3 0

3 years ago

Brian ordered a 12-inch pizza for him and some friends. They ate half of the pizza before they started

Arisa [49]

Answer:

Step-by-step explanation:

5 0

2 years ago

Five students go through the lunch line.Each student pays $1.85 for their lunch and gets 3 cookies.The total amount paid is $20.

erastovalidia [21]

Hello there! The cost of a cookie is $0.72.

Start by multiplying the cost of lunch by 5 and subtract that from the total to get rid of the cost of lunch.

$1.85 x 5 = $9.25

$20 - $9.25 = $10.75

So, there were FIVE students and each bough THREE cookies. To find the cost for each cookie, first divide the total spent on cookies by 5 to get what each student spent on cookies, then by 3 to see how much each cookie cost.

$10.75/5 = $2.15

$2.15/3 = 0.716666667, which can be rounded to $0.72.

I hope this helps and have a great rest of your day!

6 0

3 years ago