To find the GCF of the two terms, continuous division must be done.
What can be used to divide both terms such that there is not a remainder?
Start small, let's take 2. It could be a GCF.
Move up higher, say 3. Yes, it can be a GCF.
To see if there might be a greater common factor, divide the constants by 3.
48/3 = 16
81/3 = 27
Upon inspection and contemplation, there is no more common factor between 16 and 27. So, 3 is the GCF.
Moving on, when it comes to variables. The variable with the least exponents is easily the GCF. For the variable m, the GCF is m2 and for n, the GCF is n.
Combining the three, we have the overall GCF = 3m2n
Answer:
4
Step-by-step explanation:
If ten people each get three slices, they will need 30 pieces.
10 x 3 = 30
Each pizza has 8 slices, so we divide 30 by 8 to get the number of pizzas needed.
30 / 8 = 3.75
You can't buy 3.75 pizzas, so you must get 4 to ensure everyone gets enough.
Quadratic formulat is used when
a^2+bx+c=0
x=
4m^2+3m-1=0
a=4
b=3
c=-1
input
x=
x=
x=
x=
x=
or
x=-1 or 1/4
Yes........its an identity
