First, write an equation system based on the problem
An equation for "the perimeter of a rectangle is 70 in" can be written as following
∴ 2l + 2w = 70 <em>(first equation)</em>
An equation for "the length is 11 in more than its width" can be written as following
∴ l = w + 11 <em>(second equation)</em>
Second, solve the equation by substitution method o find the dimension of the rectangle.
Substitute/plug l as (w+11) into the first equation
2l + 2w = 70
2(w + 11) + 2w = 70
2w + 22 + 2w = 70
4w + 22 = 70
4w = 70 - 22
4w = 48
w = 48/4
w = 12
The width of the rectangle is 12 in
Substitute w with 12 to the second equation
l = w + 11
l = 12 + 11
l = 23
The length of the rectangle is 23 in
Third, find the area of the rectangle
a = l × w
a = 23 × 12
a = 276
The area of the rectangle is 276 in²
Yes, 4^2 x 3^3 = 144 and from here on out it’s just 12 and 144 which the 12 goes into 144 12 times
Each little square is 1 inch high and 1 inch wide, so
the area of each little square is 1 square inch.
The bug figure is made of 23 little squares, so the area
of the big figure is 23 square inches.
Median is described as the number in the middle of the set (given that the set is ordered from least to greatest), so we'll first order our set.
[48 49 50 52 54 62]
We notice that there is no middle number, so we take the two numbers that share the middle space and find their mean.
50+52=102
102/2=51
The median is 51.
:)
Answer:
3 x^3 + 3 x^2 - 3
Step-by-step explanation:
Best I can give
