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Y_Kistochka [10]
3 years ago
5

1) Five hundred tickets were sold for a fundraising dinner. The receipts totaled $3312.50. Adult tickets were $7.50 each and chi

ldren’s tickets were $4.00 each. How many tickets of each type were sold? (375,125)that’s the answer I need the steps
Mathematics
2 answers:
ehidna [41]3 years ago
6 0
Number of adults' tickets (x): $7.50x + $4.00(500 - x) = $3,312.50 $7.50x + $2,000.00 - $4.00x = $3,312.50 $3.50x = $1,312.50 x = 375 
No. of children's tickets (500 - x): = 500 - 375 = 125 
Answer: 375 adults' tickets, 125 children's tickets 
Proof (Receipts totaled $3,312.50): = (375 tickets * $7.50) + (125 tickets * $4.00) = $2,812.50 + $500.00 = $3,312.50
Scilla [17]3 years ago
4 0
Have the x=the number of adult tickets sold, and y=the number of child tickets sold. 

<span>Your two equations should be: </span>
<span>7.50x+4.00y=3312.50 </span>
<span>x+y=500  
:p </span>
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