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meriva
3 years ago
13

How to solve this question

Mathematics
1 answer:
ryzh [129]3 years ago
4 0
I can tell you how to solve this problem.
You can find the areas using both the values as the radiuses (find the are of a circle).
Subtract the smaller area from the larger area and there is your answer.
Hope this helped.
Good Luck!
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Find the volume and area for the figures shown and answer the question
olga_2 [115]

Answer:

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3 years ago
Which of the following sums would be under the radical symbol to find the distance between the points (7, -1) and (-8, -9)?
Alexxandr [17]

Sadly, you didn't put any sums on your list of choices. 
In fact, I can't even find a list of choices !

To find the distance between  (7, -1)  and  (-8, -9),
you would build a sum under a square-root (radical)
symbol, and it would look something like this:

               √ ( 225 + 64 ) .
 
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You can use the substitution method.
You substitute the first equation to the second equation to get the value of x.
x + 3y = -14
x + 3(2x) = -14
x + 6x = -14
7x = -14
x = -14/7 = -2

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7 0
3 years ago
A 26-inch long painting is how many yards long
ASHA 777 [7]
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8 0
3 years ago
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∠ACE is formed by two secants intersecting outside of a circle. If minor arc BD = 25°, minor arc AB = 115°, and minor arc DE = 1
dmitriy555 [2]

Answer:

m∠ACE = 40°

Step-by-step explanation:

Consider the below figure attached with this question.

Given information: arc BD = 25°, minor arc AB = 115°, and minor arc DE = 115°.

We need to find the measure of ∠ACE.

minor arc AB + minor arc BD + minor arc DE + minor arc AE = 360°

115° + 25° + 115° + minor arc AE = 360°

255° + minor arc AE = 360°

minor arc AE = 360° - 255°

minor arc AE = 105°

The measure of minor arc AE is 105°.

Using Intersecting secants outside the circle theorem

Angle between two secants = \frac{1}{2}(Major arc - Minor arc)

\angle ACE=\frac{1}{2}[Arc(AE)-Arc(BD)]

\angle ACE=\frac{1}{2}[105-25]

\angle ACE=\frac{1}{2}[80]

\angle ACE=40

Therefore, the measure of ∠ACE is 40°.

3 0
3 years ago
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