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3 years ago

Please help last question

Mathematics

2 answers:

Artyom0805 [142]3 years ago

7 0

so I think 37\12 is the answer to this question

Alex3 years ago

5 0

I believe the answer is 37/12. Hope this helps!

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1. What is the median of this data? 6. 12, 7, 5, 11. 6 and 9.

anastassius [24]

The median would be 7.

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3 years ago

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The teachers’ editions of a statistics textbook sell for $150 each, and students’ editions of the book sell for $50 each. Which

Novay_Z [31]

Answer:

(300 + 50x)/(2 + x)

Step-by-step explanation:

Let the cost of teachers' edition books be t

Let the cost of students' edition books be s

So t = 150; s = 50

Then the total cost of 2 teachers' editions and x students' editions is 2t + sx = 2 × 150 + 50x = 300 + 50x.

The total number of books is 2 + x.

So the average cost per book is (300 + 50x)/(2 + x)

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2 years ago

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If Carbon 12 is named 12 because it has 6 protons

tester [92]

Answer:

Step-by-step explanation:

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2 years ago

If Javier has a car with a mass of 250,000 kg and it is acted upon with a force of 300 Newtons. What is the acceleration?

natima [27]

Answer:

The acceleration is 0.0012 meters/seconds²

Step-by-step explanation:

1. Let's review the information given to answer the question correctly:

Mass = 250,000 kg

Force = 300 Newtons

2. What is the acceleration?

Based on Newton's Second Law of Motion, let's recall that:

Force = Mass * Acceleration

Acceleration = Force/Mass

Replacing with the real values, we have:

Acceleration = 300/250,0000

Acceleration = 0.0012 meters/seconds² (we can't express acceleration using Newtons/kilograms as the unit).

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3 years ago

Solve the equation on the interval [0, 2pi): 12cos^2 x-9=0 What to do?

siniylev [52]

Answer:

$\large\boxed{x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}}$

Step-by-step explanation:

$12\cos^2x-9=0\qquad\text{add 9 to both sides}\\\\12\cos^2x=9\qquad\text{divide both sides by 12}\\\\\cos^2x=\dfrac{9}{12}\\\\\cos^2x=\dfrac{9:3}{12:3}\\\\\cos^2x=\dfrac{3}{4}\to\cos x=\pm\sqrt{\dfrac{3}{4}}\\\\\cos x=\pm\dfrac{\sqrt3}{2}\\\\\text{Look at the picture}\\\\x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}$

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3 years ago