Please help if you can! thanks!

I have no idea. Please I need just answers. Thank you.

igomit [66]

Answer:

Step-by-step explanation:

1km = 1000m

5a. 5.768km = 5768m = 57.7m

5b. 9.039km = 9039m = 90.4m

5c. 8.48km = 8480m = 84.8m

5d. 17.685km = 17685m = 17.7m

5e. 17.658km = 17658m = 17.7m

To round to the nearest 100m just divide by 100 and then round it off. like 57.68=57.7m because 8 is more than 5 so 6 becomes 7 to one decimal.

Rule is applied for all the other questions too.

3 0

3 years ago

Help me decrease 25 by 30%

Marysya12 [62]

Step-by-step explanation:

Percentage decrease = 30% × 25

New value = 25 - Percentage decreaseNew value =

25 - Percentage decrease =

25 - (30% × 25) =

25 - 30% × 25 =

(1 - 30%) × 25 =

(100% - 30%) × 25 =

70% × 25 =

70 ÷ 100 × 25 =

70 × 25 ÷ 100 =

1,750 ÷ 100 =

17.5

Absolute change (actual difference) =

New value - 25 =

17.5 - 25 =

- 7.5

8 0

3 years ago

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Which expressions ere equivalent to x+x+x+2

Andrei [34K]

3x + 2

since x + x + x is 3x.

Or you can be creative

(6x+4)/2

im just trying to hit the 20 chac minimum.

3 0

3 years ago

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What is the length of AC?

Verizon [17]

AC is parallel to MN then triangle ABC and triangle MBN are similar and the ratio of the corresponding sides are equal...

3 0

3 years ago

Identify whether the series sigma notation infinity i=1 15(4)^i-1 is a convergent or divergent geometric series and find the sum

const2013 [10]

Answer: The correct option is

(d) This is a divergent geometric series. The sum cannot be found.

Step-by-step explanation: The given infinite geometric series is

$S=\sum_{i=1}^{\infty}15(4)^{i-1}.$

We are to identify whether the given geometric series is convergent or divergent. If convergent, we are to find the sum of the series.

We have the D' Alembert's ratio test, states as follows:

Let, $\sum_{i=1}^{\infty}a_i$ is an infinite series, with complex coefficients $a_i$ and we consider the following limit:

$L=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}.$

Then, the series will be convergent if L < 1 and divergent if L > 1.

For the given series, we have

$a_i=15(4)^{i-1},\\\\a_{i+1}=15(4)^i.$

So, the limit is given by

$L\\\\\\=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i-1}}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i}4^{-1}}\\\\\\=\dfrac{1}{4^{-1}}\\\\=4>1.$

Therefore, L >1, and so the given series is divergent and hence we cannot find the sum.

Thuds, (d) is the correct option.

7 0

4 years ago

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