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ahrayia [7]
3 years ago
14

Please help if you can! thanks!

Mathematics
1 answer:
makkiz [27]3 years ago
4 0
The first one in 35 ft
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I have no idea. Please I need just answers. Thank you. ​
igomit [66]

Answer:

Step-by-step explanation:

1km = 1000m

5a. 5.768km = 5768m = 57.7m

5b. 9.039km = 9039m = 90.4m

5c. 8.48km = 8480m = 84.8m

5d. 17.685km = 17685m = 17.7m

5e. 17.658km = 17658m = 17.7m

To round to the nearest 100m just divide by 100 and then round it off. like 57.68=57.7m because 8 is more than 5 so 6 becomes 7 to one decimal.

Rule is applied for all the other questions too.

3 0
3 years ago
Help me decrease 25 by 30%
Marysya12 [62]

Step-by-step explanation:

Percentage decrease = 30% × 25

New value = 25 - Percentage decreaseNew value =

25 - Percentage decrease =

25 - (30% × 25) =

25 - 30% × 25 =

(1 - 30%) × 25 =

(100% - 30%) × 25 =

70% × 25 =

70 ÷ 100 × 25 =

70 × 25 ÷ 100 =

1,750 ÷ 100 =

17.5

Absolute change (actual difference) =

New value - 25 =

17.5 - 25 =

- 7.5

8 0
3 years ago
Read 2 more answers
Which expressions ere equivalent to x+x+x+2​
Andrei [34K]

3x + 2

since x + x + x is 3x.

Or you can be creative

(6x+4)/2

im just trying to hit the 20 chac minimum.

3 0
3 years ago
Read 2 more answers
What is the length of AC?
Verizon [17]
AC is parallel to MN then triangle ABC and triangle MBN are similar and the ratio of the corresponding sides are equal...
3 0
3 years ago
Identify whether the series sigma notation infinity i=1 15(4)^i-1 is a convergent or divergent geometric series and find the sum
const2013 [10]

Answer:  The correct option is

(d) This is a divergent geometric series. The sum cannot be found.

Step-by-step explanation: The given infinite geometric series is

S=\sum_{i=1}^{\infty}15(4)^{i-1}.

We are to identify whether the given geometric series is convergent or divergent. If convergent, we are to find the sum of the series.

We have the D' Alembert's ratio test, states as follows:

Let, \sum_{i=1}^{\infty}a_i is an infinite series, with complex coefficients a_i and we consider the following limit:

L=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}.

Then, the series will be convergent if  L < 1 and divergent if  L > 1.

For the given series, we have

a_i=15(4)^{i-1},\\\\a_{i+1}=15(4)^i.

So, the limit is given by

L\\\\\\=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i-1}}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i}4^{-1}}\\\\\\=\dfrac{1}{4^{-1}}\\\\=4>1.

Therefore, L >1, and so the given series is divergent and hence we cannot find the sum.

Thuds, (d) is the correct option.

7 0
4 years ago
Read 2 more answers
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