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katrin2010 [14]
3 years ago
9

Steven rode a bike for 132.8 miles while training for a marathon. He biked 8.3 miles each day. How many days did he train for th

e marathon?
Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
8 0
8.3x=132.8
Divide 132.8 into 8.3 groups
tekilochka [14]3 years ago
6 0
It's easy, simply divide 132.8 by 8.3  and you get an answer of 16. To check, multiply 16 by 8.3 and you get 132.8. :)

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1. Find the value of x.<br><br> A. 90<br> B. 80<br> C. 60<br> D. 45
tia_tia [17]

Answer:

A 90

Step-by-step explanation:

multiple ways to prove this.

e.g. since the angle between the two lines from the center of the circle to the 2 tangent touching points is 90 degrees (that is the meaning of these 90 degrees here as the angle of the circle segment defined by the 2 tangent touching points and the circle center), the tangents have the same "behavior" as tan and cot = the tangents at the norm circle at 0 and 90 degrees. they hit each other outside of the circle again at 90 degrees.

another way

imagine the two right triangles of the tangents crossing point to the circle center and the tangent/circle touching points.

the Hypotenuse of each triangle is cutting the 90 degree angle of the circle segment exactly in half (due to the symmetry principle). so the angle between radius side and Hypotenuse is 90/2 = 45 degrees.

that means also the angle of such a right triangle at the tangent crossing point is 45 degrees (as the sum of all angles in a triangle must be 180, we have the remainder of 180 - 90 - 45 = 45 degrees).

the angles of both right triangles at that point are the same, and so we can add 45+45 = 90 degrees for the total angle at the tangent crossing point.

8 0
3 years ago
Sort 7/10,1/2,3/5,3/4 from least to greatest .
satela [25.4K]

Answer:

1

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
CO 5<br> What is the value of tan(60°)?<br> A<br> O<br> 12<br> 30°<br> 3<br> B<br> 60°<br> 6
lukranit [14]

Answer:

<em>√3</em>

Step-by-step explanation:

5 0
2 years ago
If $x$, $y$, and $z$ are positive integers such that $6xyz+30xy+21xz+2yz+105x+10y+7z=812$, find $x+y+z$.
harina [27]

Answer:

10

Step-by-step explanation:

When we simplify we get $$z(6xy+21x+2y+7)+30xy+105x+10y=812.$$

Then we continue to factor to get: (z+5)(6xy+21x+2y+7)&=847.

We then see that we can factor (6xy+21x+2y+7) into (z+5)(3x+1)(2y+7)&=847.

we then do the prime factorization of 847, which i think is,  7*11*11. we have to find the numbers that multiply to 847 and then plug them into z+5, 3x=1,2y+7.

It has to be a positive, non-negative integer, right?

We also see that 3x+1=11 so we see that x=10/3 (which wont work).

So 3x+1=7, so x=2.

So 11 has to be in another term. It has to be in 2y+7=11 so y=2

for the last term we get z+5=11 so z=6

2+2+6=10

Hope this helps and if you want please consider giving me brainliest. :)

8 0
3 years ago
Help on this one please??
xenn [34]

Answer:

C = ~50 deg

Step-by-step explanation:

Apply the cosine theorem:

cos(C) = (CA^2 + CB^2 - AB^2)/(2*CA*CB)

           = (7.5^2 + 6.5^2 - 6^2)/(2*7.5*6.5)

           = 0.6410

=> C = ~50 deg

Hope this helps!

7 0
3 years ago
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